The underlying assumption is that each person shakes the hand of each other person. If there are "n" people, each will shake the hands of "n-1" other people. To avoid counting double, the result has to be divided by 2. Therefor, the number of handshakes is equal to n(n-1)/2. Trying this out for several values of "n" should be faster than using the quadratic formula. (If you use the quadratic formula, you will probably get a positive and a negative solution - you can discard the negative solution.)
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Ask him to go with you to the party
Will have.ANDwill have -- I will have a headache if you don't shut up.going to have -- We are going to have a party next week.am/is/are having -- They are having a party tonight.
Forward contracts are very similar to futures contracts, except they are not marked to market, exchange traded, or defined on standardized assets. Forwards also typically have no interim partial settlements or "true-ups" in margin requirements like futures - such that the parties do not exchange additional property securing the party at gain and the entire unrealized gain or loss builds up while the contract is open. A forward contract arrangement might call for the loss party to pledge collateral or additional collateral to better secure the party at gain. (Wikipedia)
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107 unique handshakes will be exchanged
If that happens you have to times ninexten and the answer would be 90 handshakes
With 3 people, there are only 3 handshakes: AB, AC, and BC. Where it gets interesting is at a party with, say, 10 people ... 45 handshakes. Or in the US Senate when all 100 Senators are present ... 4,950 handshakes.
Sixty-six unique, distinct handshakes.
So, there will be 3 handshakes among the 3 people at the party.
29 People including You.
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There will be 28 handshakes. If you ask each person how many handshakes they had they will tell you 7 making 7 x 8 = 56 handshakes in all. But every hand involves two people, so every handshake has been counted twice, thus there are 56 / 2 = 28 handshakes in all.
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Each handshake involves two people. If everyone shook only once then there were 36 x 2 ie 72 guests.
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There were ten people at the party. This is a triangular sequence starting with two people: 1, 3, 6, 10, 15, 21, 28, 36, 45, etc. There's an equation for this. With n people at the party, the number of handshakes is n(n-1)/2.