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Anonymous
No, 8 is a multiple of 2, since it is 4 x2, but 2 is less than 8 so it can't be a multiple.
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[(log1)/2](8)=(0/2)(8)=0
x-2+4=-8 x+2=-8 x=-10
If2 + 8 = 8 + xx = 2
When Y = 8, Y - 2 = 6.