A = A0 e-Bt
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That all depends on the problem given!A general form of the exponential growth/decay is:y = ab^x.If we have an exponential growth, b = 1 + rOtherwise, b = 1 - r.In the second version, the exponential growth is y = Ae^(kt) while the exponential decay is y = Ae^(-kt)
Yes.
The process of decreasing in number, size, quantity, or extent.Decrease, loss, decrement, reduction, diminution, decline, decay, etc. Decrement.
Well, sweetheart, the integral of dV/V is simply ln|V| + C, where C is the constant of integration. So, in other words, the integral of dV/V is the natural logarithm of the absolute value of V, plus some boring constant. Math can be a real snoozefest, but hey, at least now you know the answer!
Use Q = Q0e-kt, where Q0 is the initial amount of uranium and k is the factor of proportionality. Since we know that Q = 1/2 Q0 when t = 74, we have 1/2Q0 = Q0e-k x 74; 1/2 = e -74k; In 1/2 = -74k; k = 0.009366853