The form of a function is y = mx + b (with m being the slope and b the point at which the function crosses the y-axis), so you have to isolate the y. To do this, you can first subtract 2x from sides to reach -4y = 4 - 2x, or -4y = -2x + 4; you're practically there already. All you have to do then is divide everything by -4 to obtain y = 1/2 x -1. You have successfully isolated the y and moved the variables to equal the form y = mx + b, so you are done.
5x + 5y = 19x = 3.8 - yory = 3.8 - x
X-y=1
No, y=x^2 + 2 is a quadratic equation. A linear equation is one in the form y=mx+b. A quadratic has a form y=ax^2+bx+c.
If: 5x+2y = 9 Then: y = -2.5x+4.5 in slope intercept form
It is a quadratic equation and can be rearranged in the form of:- x2-x-6 = 0 (x+2)(x-3) = 0 Solutions: x = -2 and x = 3
y=3x+12
23
== == y = -x + 5
69
7x = -3y + 12
y = -x-2
The equation of the line is written in the standard form, y = mx+c
y=-x+8
-8
It is: y = x-1
-3
5x + 5y = 19x = 3.8 - yory = 3.8 - x