multiply a by x then add the product of c and y. Your answer would be, based on the value of a,x,c,y, like this.
ax + cy = ??
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
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Assuming the formula that was meant was x^2 plus 8x minus 5 equals 0 [ x^2 + 8x - 5 = 0 ] the quadratic formula uses the standard form of a quadratic ax^2 plus bx plus c = 0 [ax^2 + bx + c = 0] comparing this form to the equation we get a = 1 b = 8 and c = -5 the quadratic formula is: x = negative b plus or minus the square root of (b^2 minus 4ac) all over 2a [ x = (-b +- root(b^2 - 4ac))/2a ] if we substitute in the values we have for a, b and c we get x = negative 8 plus or minus the square root of (8^2 minus 4*1*(-5)) all over 2*1 [ x = (-8 +- root(8^2 - 4*1*(-5)))/(2*1) ] simplified we get x = (-8 +- root(64 + 20))/2 and x = (-8 +- root(84))/2 and x = (-8 +- 2*root(21))/2 we get two solutions x = (-8 - 2*root(21))/2 x approx= (-8.58) and x = (-8 + 2*root(21))/2 x approx= (.58)
No, y=x^2 + 2 is a quadratic equation. A linear equation is one in the form y=mx+b. A quadratic has a form y=ax^2+bx+c.
let f(x) = ax if a is a constant, then f'(x) = a if a is not constant, then f'(x) = ax' + a'x
ax - b = c ax = b + c x = (b + c)/a
It is a straight line with gradient -A/B and intercept C/B.
Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)
ax + b = 15 or ax + b = -15
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
a function
Your two equations are: AX + BY = A - B BX - AY = A + B + B Because you have four variables (A, B, X, Y), you cannot solve for numerical values for X and Y. There are a total of four answers to this question, solving each equation for X and Y independently. First equation: X = (A - B - BY)/A Y= (A - B - AX)/B Second equation: X = (A +2B +AY)/B Y = (BX - A - 2B)/A
Ax + By = C By = -Ax + C y = (-A/B)x + C/B
Solve the equation for y. This will give you an equation similar to y = ax + b, where a is the slope, and b is the y-intercept.
A linear equation.
x = -c/(a+b), provided a+b is not 0
x = (d-a)/(a-c)