Q: How do you solve x plus 2X equals 33?

Write your answer...

Submit

Still have questions?

Continue Learning about Calculus

2×11 -33 22-33 -11 1 11---1

8x + 33 = 7x + 27 Subtract 7x from both sides: x + 33 = 27 Subtract 33 from both sides: x = -6

2x + 6y = 93x - 12y = 15Chose the second equation because you can simplify it.3x - 12y = 15 divide by 3 to both sidesx - 4y = 5 add 4y to both sidesx = 4y + 5Replace 4y + 5 for x to the first equation.2x + 6y = 92(4y + 5) + 6y = 98y + 10 + 6y = 914y = -1y = -1/14x = 4y + 5x = 4(-1/14) + 5x = -2/7 + 5x = -2/7 + 35/7x = 33/7

Twenty-Five x2 + 10x = 8 x2 + 10x + 25 = 8 + 25 (x + 5)2 = 33

-6y - 9 = 5y + 24Add 6y to each side of the equation:-9 = 11y + 24Subtract 24 from each side:-33 = 11yDivide each side by 11:-3 = y

Related questions

88+x=3x+22 88=2x+22 66=2x x=33

Then x = 6 Therefore; 5x + 3 = 33 First you have to solve the value of X: 8X + 5X + 2X +4X = 114; OR 19x = 114. When you divide both sides of the equation by 19 to solve for X, you find that X = 6. Ergo, 5X + 3 = 30 + 3 = 33; hence, 5X + 3 = 33.

33

2x + 33 = 4x + 11 -11 -11 2x + 22 = 4x -2x -2x 22 = 4x Divide each side by 4 x = 5.5

x = 59

8x + 11 = 33 + 6x 8x - 6x = 33 - 11 2x = 22 x = 11

It is a linear equation in one variable, x. Oh, I suppose you want the solution? 2x + 33 = 4x + 11 Subtract 2x from both sides: 33 = 2x +11 Subtract 11 from both sides: 22 = 2x Divide both sides by 2: 11 = x

It can be simplified to: 2x+33

2x + 6 + 9x = 39 11x + 6 = 39 11x = 39 - 6 11x = 33 x = 3

14c+33-10c=5 4c+33=5 4c=-28 c=-7

So 17 = 9x, making x = 1 and 8/9

8x + 5x + 2x + 4x = 114 19x = 114 x = 6 then 5x + 3 = 5*6 + 3 = 33