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How do you use double integrals to find the surface area of two intersecting cylinders of radius 1?
Wiki User
∙ 15y ago
To find the area of one cylinder you integrate over dh and dt (theta) like this: r.dt.dh with dt from 0 to 2pi radians. The intersection changes the limits of theta. Assuming that the center of the second cylinder is exactly R from the other cylinder then theta goes from 0 to 2pi*2/3. The 2/3 is because you have removed 120 degrees. However you now have two cylinders so you need to double it to: 2*2pi*2/3 which when factor in the height H and radius R gives you 8pi/3*R*H
Wiki User
∙ 15y ago
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