g(x) = x + 3
Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
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Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
a constant
Yes, the integral of gx dx is g integral x dx. In this case, g is unrelated to x, so it can be treated as constant and pulled outside of the integration.
Domain is the number of x values that can be used and not cause an imaginary result. Range is the number of the y values that result. In f(x)=2x-5 the range is all real numbers.
f(x)=5x+2
If you are talking about f(x) then yes it is the same as y
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
please elaborate your question
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y = 3x + 2x^2 + k where k is any number
False
I plotted it and found that it crosses the x-axis at x = -2, -1, then approx -0.77 and approx 0.434, so I factored (using long division) (x+2) and (x+1), to get 3x2 + x -1 as a factor. Using the quadratic formula gives:(-1 - sqrt(13))/6 and (-1 + sqrt(13))/6as the exact values for -0.77 & 0.434
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x = ¼x^4 + 4x + k where k can be any number