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If x varies jointly as y and the square as z and x equals 40 when y equals 20 and z equals 2 find x when y equals 30 and z equals 3?
Wiki User
∙ 12y ago
As x ∝ yz2 then x = kyz2 where k is a constant.
Substituting the given figures, 40 = k*20*22 = 80k
Then k = ½ and the formula is, x = ½yz2
So, x = ½ * 30 *32 = 135
Wiki User
∙ 12y ago
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