As x ∝ yz2 then x = kyz2 where k is a constant.
Substituting the given figures, 40 = k*20*22 = 80k
Then k = ½ and the formula is, x = ½yz2
So, x = ½ * 30 *32 = 135
y is 12
x = 24
1
Lets take 9 for example. If you want to find the square root you just find what number times its self equals 9. So in this case it would be 3.
y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22
a = 0.8
x = 75
f = 54
25
135
80=4x, z=6x. find Z. x=80/4, x=20. z=6x20 z=120 answer= 120
If P varies jointly as q, r and s - assume this is in direct proportion, then P ∝ qrs so P = kqrs where k is a constant.70 = k x 7 x 5 x 4 = 140k : k = 140/70 = 0.5When q = 2, r = 15 and s = 7 then,P = 0.5 x 2 x 15 x 7 = 105
If P varies directly with q, r and s then P = kqrs, where k is a constant. As 70 = k x 7 x 5 x 4 = 140k : k = 70/140 = 1/2 The equation of joint variation is P = ½qrs.
57
40
y = -5
80