The relationship Y = kx is proportional, where Y is directly proportional to x with a constant of proportionality k. This means that as x increases, Y also increases in a linear fashion. In a nonproportional relationship, the ratio of Y to x would not be constant, and the relationship could be more complex, such as quadratic or exponential.
y=54 if x=6 so we can write y=9(x) so y=k(x) clearly y is directly proportional to x.
The answer depends on how the information is presented. If in the form of a graph, it must be a straight line through the origin. If in the form of an equation, it must be of the form y = cx.
y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22
The question is not clear. But if you want this in the form y=kx, then k must be 1.5
if INVERSELY proportional then y = 1/X^2 ( that is, 1 divided by x squared) If X doubles then X SQUARED increases as 2 x 2 = 4 times SINCE Y = 1/x^2 then Y DECREASES 4 times
The answer is proportional.
The graph of a linear proportion will be a straight line passing through the origin. The equation will have the form y = mx, also written as y = kx.
Generally, if y increases as x increases, this is a hint that the quantity is directly proportional, and if y decreases as x increases, the relation might be inversely proportional. However, this is not always the case. x and y are directly proportional if y = kx, where k is a constant. x and y are inversely proportional if y = k/x, k is constant. This is the best way to tell whether the quantities are directly or inversely proportional.
Various options: y is directly proportional to k, with x as the constant of proportionality; y is directly proportional to x, with k as the constant of proportionality; x is inversely proportional to k, with y as the constant of proportionality; x is directly proportional to y, with 1/k as the constant of proportionality; k is directly proportional to y, with 1/x as the constant of proportionality; and k is inversely proportional to x, with y as the constant of proportionality.
A proportional relationship is of the form y = kx where k is a constant. This can be rearranged to give: y = kx → k = y/x If the relationship in a table between to variables is a proportional one, then divide the elements of one column by the corresponding elements of the other column; if the result of each division is the same value, then the data is in a proportional relationship. If the data in the table is measured data, then the data is likely to be rounded, so the divisions also need to be rounded (to the appropriate degree).
Two quantities are directly proportional if they increase or decrease at a constant rate or ratio. This means that as one quantity increases, the other also increases, and vice versa. Mathematically, this relationship is expressed as y = kx, where y is directly proportional to x, and k is the constant of proportionality.
No. A proportional relationship between "y" and "x" must be of the form:y = kx where "k" can be any constant. Thus, y = 16x would work perfectly. However, the additional "+4" makes it impossible to convert it to this form.
y varies directly with x means y = kx, where k is the constant of the variation. When x = 2.5 and y = 5, we have y = kx 5 = 2.5k k = 2 When x = 10, y = kx y = (2)(10) y = 20
When two variables are directly proportional, it means that as one variable increases, the other variable also increases at a constant rate. In mathematical terms, this relationship can be expressed as y = kx, where y is one variable, x is the other variable, and k is a constant value.
y=54 if x=6 so we can write y=9(x) so y=k(x) clearly y is directly proportional to x.
direct variation: y = kx y = kx k = y/x = 0.8/0.4 = 2
A proportional relationship exists when two variables are related by a constant ratio. In the expression y-2.5x, there is no constant multiplier connecting y and x, indicating a non-proportional relationship. If the relationship were proportional, the expression would be in the form y = kx, where k is a constant.