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The relationship Y = kx is proportional, where Y is directly proportional to x with a constant of proportionality k. This means that as x increases, Y also increases in a linear fashion. In a nonproportional relationship, the ratio of Y to x would not be constant, and the relationship could be more complex, such as quadratic or exponential.
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Does y varies directly with x if y54 when x 6?
y=54 if x=6 so we can write y=9(x) so y=k(x) clearly y is directly proportional to x.
How do you know the relationship between x and y is proportional?
The answer depends on how the information is presented. If in the form of a graph, it must be a straight line through the origin. If in the form of an equation, it must be of the form y = cx.
If y Varies Directly as x to the 2nd power and y equals 198 when x equals 6 find y when x equals 2?
y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22
In the direct variation 2y equals 3x what is the k value?
The question is not clear. But if you want this in the form y=kx, then k must be 1.5
If y is inversely proportional to the square of x fully explain what happens when x is doubled?
if INVERSELY proportional then y = 1/X^2 ( that is, 1 divided by x squared) If X doubles then X SQUARED increases as 2 x 2 = 4 times SINCE Y = 1/x^2 then Y DECREASES 4 times
