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It is directly proportional.
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Does y varies directly with x if y54 when x 6?
y=54 if x=6 so we can write y=9(x) so y=k(x) clearly y is directly proportional to x.
How do you know the relationship between x and y is proportional?
The answer depends on how the information is presented. If in the form of a graph, it must be a straight line through the origin. If in the form of an equation, it must be of the form y = cx.
If y Varies Directly as x to the 2nd power and y equals 198 when x equals 6 find y when x equals 2?
y=kx^2 hence k=198/36. now y=198/36*(2)^2 y=22
In the direct variation 2y equals 3x what is the k value?
The question is not clear. But if you want this in the form y=kx, then k must be 1.5
If y is inversely proportional to the square of x fully explain what happens when x is doubled?
if INVERSELY proportional then y = 1/X^2 ( that is, 1 divided by x squared) If X doubles then X SQUARED increases as 2 x 2 = 4 times SINCE Y = 1/x^2 then Y DECREASES 4 times
If two quantities are (proportional nonproportional) they have a constant ratio.?
The answer is proportional.
What is proportional linear relationship in math?
The graph of a linear proportion will be a straight line passing through the origin. The equation will have the form y = mx, also written as y = kx.
How do you tell if a math table is inversely proportional or directly proportional?
Generally, if y increases as x increases, this is a hint that the quantity is directly proportional, and if y decreases as x increases, the relation might be inversely proportional. However, this is not always the case. x and y are directly proportional if y = kx, where k is a constant. x and y are inversely proportional if y = k/x, k is constant. This is the best way to tell whether the quantities are directly or inversely proportional.
If y equals kx then what is the relationship between x y and k?
Various options: y is directly proportional to k, with x as the constant of proportionality; y is directly proportional to x, with k as the constant of proportionality; x is inversely proportional to k, with y as the constant of proportionality; x is directly proportional to y, with 1/k as the constant of proportionality; k is directly proportional to y, with 1/x as the constant of proportionality; and k is inversely proportional to x, with y as the constant of proportionality.
How do you determine whether a relationship shown in a table is a proportional relationship?
A proportional relationship is of the form y = kx where k is a constant. This can be rearranged to give: y = kx → k = y/x If the relationship in a table between to variables is a proportional one, then divide the elements of one column by the corresponding elements of the other column; if the result of each division is the same value, then the data is in a proportional relationship. If the data in the table is measured data, then the data is likely to be rounded, so the divisions also need to be rounded (to the appropriate degree).
Is the equation y equals 16x plus 4 a proportional relationship?
No. A proportional relationship between "y" and "x" must be of the form:y = kx where "k" can be any constant. Thus, y = 16x would work perfectly. However, the additional "+4" makes it impossible to convert it to this form.
If Y is 5 when x is 2.5 and y varies directly with x find y when x is 10?
y varies directly with x means y = kx, where k is the constant of the variation. When x = 2.5 and y = 5, we have y = kx 5 = 2.5k k = 2 When x = 10, y = kx y = (2)(10) y = 20
Does y varies directly with x if y54 when x 6?
y=54 if x=6 so we can write y=9(x) so y=k(x) clearly y is directly proportional to x.
Find a equation of variation where y varies directly as x and y equals 0.8 when x equals 0.4?
direct variation: y = kx y = kx k = y/x = 0.8/0.4 = 2
Is y-2.5x a proportional relationship or no?
no a proportional relationship is y / x = 5
What is inversly proportional?
x is inversely proportional to y when x = 1/y.
What are the values of k when the line kx plus y equals 4 touches the curve y equals x squared plus 8 on the Cartesian plane showing work?
If: y = x^2 +8 and kx +y = 4 or y = 4 -kx Then: x^2 +8 = 4 -kx So: x^2 +8 -4 +kx = 0 => x^2 +4 +kx = 0 Using the discriminant b^2 -4ac = 0: k^2 -4*1*4 = 0 => k^2 = 16 Therefore the values of k are: -4 or 4 Hence: y-4x = 4 and y+4x = 4 are tangents to the curve y = x^2 +8
