I understand your question to be this:
x√2 = 4-7x
So I would plus 7x to both sides to get this: x√2 + 7x = 4
Then take x out of the bracket to get this: x(√2 + 7) = 4
Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)
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49/4 or 12.25
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3
It is not possible to solve one equation in two unknowns (x and y). Two independent equations are required.
(1) 5x+y=-12 (2) 7x-3y=-30 From (1) one gets y = -12-5x Put into (2) 7x-3y = 7x -3 (-12-5x) = 7x + 36 +15 x = 22x +36=-30 22x = -30-36 = -66 so x = -3 and y=-12-5x = -12-5x-3= 3 The solution is (-3,3)
7x = 5+5x 7x-5x = 5 2x = 5 x = 2.5