why will the equations x+14=37 and x-14=37 have different solutions for x
X + 11 = 37. subtract 11 from both sides; X = 37 - 11 = 26.
Divide both sides by 64 to find the value of x
So if I understand your question correct, it should be 37+Y=87Y?
1-37
if x2 + 7 = 37, then x2 = 29 and x = ±√29
X + 11 = 37. subtract 11 from both sides; X = 37 - 11 = 26.
It does not help you.
It is a linear equation in the variable z.
11 So: x = 37
n+37=83.
32
64x = 37 Divide both sides by 64: x = 37/64 or 0.578125
If: 6+y =37 Then: y = 31
To solve for ( y ) in the equation ( 375 = 37 + 26y ), first subtract 37 from both sides: ( 375 - 37 = 26y ), which simplifies to ( 338 = 26y ). Next, divide both sides by 26: ( y = \frac{338}{26} ). Thus, ( y = 13 ).
It is an equation and the value of x is 12
22+2x = 37+6+x 2x-x = 37+6-22 x = 21
To make the equation true with parentheses, you can place them around the addition: (37 + 48) = 264. This implies that 37 plus 48 equals 85, which does not equal 264. Therefore, there are no placements of parentheses that can make the equation true as written.