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7x - 9y = 35
-3x + 6y = -15 (divide the second equation by 3, after that multiply it by 7)

7x - 9y = 35
-7x + 14y = -35 (add both equations)

5y = 0 (divide both sides by 5)
y = 0

7x - 9y = 35 (substitute 0 for y)
7x = 35 (divide both sides by 7)
x = 5

Thus the solution of the given system of the equations is x = 5 and y = 0.

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Q: Solve the system by the elimination method 7x-9y equals 35 plus -3x plus 6yequals -15?
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