7x - 9y = 35
-3x + 6y = -15 (divide the second equation by 3, after that multiply it by 7)
7x - 9y = 35
-7x + 14y = -35 (add both equations)
5y = 0 (divide both sides by 5)
y = 0
7x - 9y = 35 (substitute 0 for y)
7x = 35 (divide both sides by 7)
x = 5
Thus the solution of the given system of the equations is x = 5 and y = 0.
x + 4y = -14 eqn12x + 3y = 13 eqn2Using the elimination method we multiply eqn1 by 22x + 8y = -28 eqn1bSubtract eqn2 from eqn1b2x + 8y = -28 eqn1b2x + 3y = 13 eqn25y =-41y = -8 and 1/5substituting this into eqn1 we getx +4 (-41/5) = -14x = (14*5) / (41 *4)x = (35/82)
7
y = -24x - 3y = 18 (use the substitution method)4x - 3y = 18 (substitute -2 for y, and solve for x))4x - 3(-2) = 184x + 6 = 18 (subtract 6 to both sides)4x = 12 (divide by 2 to both sides)x = 3Thus, (3, -2) is the solution of the given system of equations.
It is a simultaneous equation and its solution is x = -1 and y = -5
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
By elimination: x = 3 and y = 0
Simultaneous equations can be solved using the elimination method.
Solve the system by the elimination method 5x 5y-13 7x-3y17what is the solution to the system?
Solving by elimination: p = 3 and q = -2
x + 4y = -14 eqn12x + 3y = 13 eqn2Using the elimination method we multiply eqn1 by 22x + 8y = -28 eqn1bSubtract eqn2 from eqn1b2x + 8y = -28 eqn1b2x + 3y = 13 eqn25y =-41y = -8 and 1/5substituting this into eqn1 we getx +4 (-41/5) = -14x = (14*5) / (41 *4)x = (35/82)
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
It is called solving by elimination.
the answer
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
There is no simple answer. Sometimes, the nature of one of the equations lends itself to the substitution method but at other times, elimination is better. If they are non-linear equations, and there is an easy substitution then that is the best approach. With linear equations, using the inverse matrix is the fastest method.
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
Multiply every term in both equations by any number that is not 0 or 1, and has not been posted in our discussion already. Then solve the new system you have created using elimination or substitution method:6x + 9y = -310x - 6y = 58