The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a 0.015kg sample of lead by 10 degrees Celsius?

Answer 1

The relevant equation behind this problem is

Q=m*c* ΔT

Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that

Q=.015kg * 128J/(kg*C) * 10C=19.2J.

Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.

Answer 2

50

Answer 3

19.2

Answer 4

.09

Answer 5

19.2