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The relevant equation behind this problem is

Q=m*c* ΔT

Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that

Q=.015kg * 128J/(kg*C) * 10C=19.2J.

Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.

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Wiki User

14y ago
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Carlie Hayes

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2y ago
thanks
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Anonymous

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4y ago

50

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Anonymous

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4y ago

19.2

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Anonymous

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4y ago

.09

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Anonymous

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4y ago

19.2

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