12x - 5 = 30
Add 5 to each side:
12x = 35
Divide each side by 12:
x = 35/12
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y = 2x - 6
Substitute the value of 'x' :
y = 2(35/12) - 6
Clear parentheses:
y = 35/6 - 6
y = 35/6 - 36/6
y = -1/6
2x - 3y = -15x => -3y = -17x => -21y = -119x 2x - 3y = 4y => 2x = 7y => 21y = 6x so now you can add the two equations. 0 = -113x x=0 now plug back in 2*0 - 3y = -15*0 -3y = 0 y=0.
you need two equations to answer it, or you need to know the value of x.
Solve this simultaneous equation using the elimination method after rearraging these equations in the form of: 3x-y = 5 -x+y = 3 Add both equations together: 2x = 8 => x = 4 Substitute the value of x into the original equations to find the value of y: So: x = 4 and y = 7
First rearrange these simultaneous equations in the form of: 7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top equation remembering that a - - is equal to a plus. So, -4y - - 4y = 0 2x = 12 and therefore it follows that x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
9x-9y = 36 => x-y = 4 3(-y+x = 4) 7y-3x = -14 Multiply all terms in the top equation by 3: -3y+3x = 12 7y-3x = -14 Add both equations together: 4y = -2 Divide both sides by 4: y = -0.5 Substitute the value of y into the original equations to find the value of x: x = 3.5 and y = -0.5
X = 135 and y = 15 Solved by addition and substitution
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5x+8 = 10x+35x-10x = 3-8-5x = -5x = 1 and by substituting the value of x into the equations y = 13
To solve this system of equations, we can use the method of substitution or elimination. Let's use the substitution method. From the second equation, we can express y as y = 55 - 4x. Substitute this expression for y in the first equation: 7x - 5(55 - 4x) = 76. Simplify this equation to solve for x. Then, substitute the value of x back into one of the original equations to find the value of y.
2x - 3y = -15x => -3y = -17x => -21y = -119x 2x - 3y = 4y => 2x = 7y => 21y = 6x so now you can add the two equations. 0 = -113x x=0 now plug back in 2*0 - 3y = -15*0 -3y = 0 y=0.
y = 4x-8 and y = 2x+10 4x-8 = 2x+10 4x-2x = 10+8 2x = 18 x = 9 Substitute the value of x into the original equations to find the value of y: Therefore: x = 9 and y = 28
2
What is the value of what. You didnt specify. And this equations dont make sense. 100millimeters can equal 11.70 nothing and 150millimeters can equal 34.20 when 100mm equals 11.70. And what is the random 40mm for
3x+y = 10 y = x-2 Substitute the value of y into the top equation: 3x+x-2 = 10 => 4x = 10+2 => 4x = 12 => x = 3 Substitute the value of x into the original equations to find the value of y: So: x = 3 and y = 1
a) 4x+13y=40 b) 4x+3y=-40c) multiply b per(-1)=-4x-3y-40d) sum a and c: 4x+13y-4x-3y=40-(-40)=>10y=80 => y=8to find x replace y per its value in a or b and get x=-16
x=3
15