12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
7x-3=3x+8 7x-3x=8+3 4x=11 x=11/4=2.75
7x-4 = 3x+36Add 4, it cancels out.. So,7x = 3x+40Now subtract 3x from 7x..4x = 40..40 divided by 4 is 10So, X= 10
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
Here's the kind of process you can use to find out:Write the equation, so you can look at it:7x + 2 = 4x - 3Subtract 4x from each side of the equation:3x + 2 = -3Subtract 2 from each side:3x = -5Divide each side by 3:x = - 5/3
4x + 8 + 7x + 12 = 11x + 20
4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2
The answer to the math problem of 5x plus 7x-4x 6 is -12.
4x
-4x
8y-7x
3x + 4x = 7x
4x+5=7x-8 the ansewr is 3.25
3x + (-2 + 4x) = -2 + 7x
4x - 7 = 5 + 7x x = -4
-3x=-21+4x-3x-4x=-21+4x-4x-7x=-217x=217x/7=21/7x=3
13x