x = 5 y = 2 4x - 3y = ? 4(5) - 3(2) = ? 20 - 6 = 14
x2 + 4x + 3 = (x + 1)(x + 3)
(A): 4x + y = 7 (B): 2x - 3y = -7 2*(B) 4x - 6y = -14 Subtract from (A) 7y = 21 Divide both sides by 7: y = 3 Substitute in (A): 4x + 3 = 7 ie 4x = 4 or x = 1 Answer: x = 1 , y = 3
7
The equation 4x + 5 = 2 has the solution 4x = -3 and x = - 3/4 (minus 3/4).
-14 = 3x + (x-2)-14 = 3x + x -2-14 = 4x -2-12 = 4x-3 = x
x + 4x + 3 = 17(Take 3 from both sides)x + 4x = 14= 5x = 14(divide both sides by 5)x = 2.8
You solve for x 3x -3 = 4x -14 now subtract 3x from both sides - 3 = x -14 add 14 to both sides 11 = x
4x + 2 + 2x - 2x = 14 4x = 14 - 2 4x = 12 x = 3
14 + 4x - 8 = -6 4x + 6 = -6 x = (-6 + -6) / 4 x = -3
x=3 Use the basic rules of algebra. 4x+2=14 Minus 2 on both sides. 4x=12 Divide by 4 on both sides. x=3
4x + 3 = -3 + 2x + 14 2x + 3 = -3 +14 2x + 3 = 11 2x = 8 x=4
If x = 3, (4 x 3) + 14 = 26 and (6 x 3) + 8 = 26.
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
7 x - 4 x + 2 x+5 = 2 x + 14 --- (1) Shift those terms containing "x" on left side and constants on other side 7 x - 4 x + 2 x - 2 x = 14 - 5 We will get 3 x = 9 Divide both sides by "3" we get; x = 3
5x + 14 = 95 - 4x 5x + 4x = 95 - 14 9x = 81 x = 81/9 x = 9
If x = 3, 4x = 12