One-Hundred-thirty-four
100+30+2
1$ d d d p p p p
CXXXII
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C. p ‹ 12
x^(4) dx = x^(5) /5 [2,4] => 4^(5)/5 - 2^(5)/5 => 2^(10) / 5 - 2^(5) / 5 [2^(10) - 2^(5) ] / 5 = [1024 - 32] / 5 = 992/5 = 198.4
Oh, dude, it's like you're asking me to do math or something. So, when you have 5 multiplied by itself 5 times, you can write it as 5^5. It's like a shortcut for saying "5 times 5 times 5 times 5 times 5." Easy peasy lemon squeezy!
13
5X + 5 = 25 subtract 5 from each side 5X + 5 - 5 = 25 - 5 5X = 20 divide both sides integers by 5 (5/5)X = 20/5 X = 4 -----------check in original equation by inserting 4 into X place 5(4) + 5 = 25 20 + 5 = 25 25 = 25 -----------checks