So, do you mean what is 5x+3=4x? If you do, I don't think that's algebraically possible, but I'm not sure. You have to have at least one more number without a variable on the 4x side for the equation to be solvable.
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collect like terms and you get 4x + 5x + 8 - 3 ie 9x +5
9x + 5 = 4x + 3 Subtract 4x from both sides: 5x + 5 = 3 Subtract 5 from both sides: 5x = - 2 Divide both sides by 5: x = -2/5 or -0.4
It is x^3 - x^2 + 5x - 1Further Information:-Dividend: 4x^4 -x^3 +17^2 +11x +4Divisor: 4x +3Quotient: x^3 -x^2 +5x -1Remainder: 7
4x - 8 = 5x 1) Add 8 to both sides. 4x - 8 (+ 8) = 5x (+ 8) Becomes 4x = 5x + 8 2) Subtrate 5x from both sides. 4x (- 5x) = 8 Becomes -1x = 8 Reduced to -x = 8 3) Multiply both sides by -1. Becomes x = -8
Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7