x+y=-8
2x-y=4
y=-x-8
2x+x+8=4
3x=-4
x=-4/3
-4/3 + y= -8
y = -8 + 4/3
y= -6 2/3
A graph that has 1 parabolla that has a minimum and 1 positive line.
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
x=1
There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.
2x = -7 - 8y
x = 1 and y = 2
{-1,-2}
y = 0 and x = 8.
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
y=(-1) x=(2)
They are parallel.
A pair of simultaneous equations in two unknowns which are inconsistent - in the sense that there is no solution that simultaneously satisfies both equations. Graphically, the equations are those of two parallel lines (slope = 2). Since, by definition, they cannot meet there is no solution to the system.
There are two solutions and they are: x = -1 and y = 3
2x - y = 15 2x + 3y = -21 As you observe both equations (having different slopes), you see that the system is consistent, and it has only one solution.
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
They are two equations in two unknown variables (x and y), which are inconsistent. That is to say, there is no simultaneous solution. An alternative approach is to say that they are the equations of two lines in the Cartesian plane. The lines are parallel and so they do not meet indicating that there is no simultaneous solution.