(x-9)2 + y2 = 484
The center is at
x = 9
y = 0
The radius of the circle is 22 .
10
There are no exclude values of the equation, as given.
You have not given us an equation, just a term, x + 6. Every equation states that some quantity is equal to some other quantity, and this is shown by means of the equals sign (=). An example of this might be, x + 6 = 10. If that was the equation, then x = 4.
No, this is not a function. The graph would have a vertical line at x=-14. Since there are more than one y value for every given x value, the equation does not represent a function. The slope of the equation also does not exist.
C. (2, 5) d. (-4, -13)
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
(-4,3)
(-7,5)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
At the center, (x, y) = (-2, 5)
(-5, 3)
(-4, 3)
(8,-8)
(-4,-6)
The centre is (-5, 3)