The set of non-negative integers includes zero: [0,1,2,3,4,...]. These are also called whole numbers.
The set of positive integers does not include zero: [1,2,3,4...]. These are also called counting/natural numbers.
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It might seems like it, but actually no. Proof: sqrt(0) = 0 (0 is an integer, not a irrational number) sqrt(1) = 1 (1 is an integer, not irrational) sqrt(2) = irrational sqrt(3) = irrational sqrt(4) = 2 (integer) As you can see, there are more than 1 square root of a positive integer that yields an integer, not a irrational. While most of the sqrts give irrational numbers as answers, perfect squares will always give you an integer result. Note: 0 is not a positive integer. 0 is neither positive nor negative.
Yes.
X - 5 = 10 add 5 to each side X - 5 + 5 = 10 + 5 X = 15 ----------- check in original equation 15 - 5 = 10 10 = 10 checks remember, adding a positive and negative integer of the same absolute value = 0. - 5 + 5 = 0
-52x <= 7 (-52x)/(-52) >= 7/(-52) {divide both sides by -52, and reverse the inequality when dividing by a negative. x >= -7/52 There is no largest integer value for x. If the question was ... greater than or equal to ... then the solution would be x <= -7/52, and the largest integer value would be -1.
If you divide an integer by 9, the remainder can be anything from 0 to 8.If you divide an integer by 9, the remainder can be anything from 0 to 8.If you divide an integer by 9, the remainder can be anything from 0 to 8.If you divide an integer by 9, the remainder can be anything from 0 to 8.