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limx=>05x/(3sin(x)*cos(x)) = 5/3 * limx=>0(x/(sin(x)*cos(x)) = 5/3 * (1/limx=>02x)) = 5/3 * 1/1 = 5/3.
Another Summary:
As a start, you must remove the interdeterminant forms by using the L'Hopital rule:
Deriving the terms, we have:
5/3 * limx=>0(1/(cos2(x) - sin2(x)) = 5/3 * limx=>0(1/cos(2x))
Rule of Continuity:
5/3 * (1/cos(limx=>0(2x)) = 5/3 * 1/(cos(0)) = 5/3 * 1/1 = 5/3.
When we divide 1 by infinity, we are essentially taking the limit of 1 as the denominator approaches infinity. In mathematics, this limit is equal to zero. This is because as the denominator becomes infinitely large, the value of the fraction approaches zero. Therefore, 1 divided by infinity equals 0.
Calculus is about applying the idea of limits to functions in various ways. For example, the limit of the slope of a curve as the length of the curve approaches zero, or the limit of the area of rectangle as its length goes to zero. Limits are also used in the study of infinite series as in the limit of a function of xas x approaches infinity.
No, limit can tend to any finite number including 0. It is also possible that the limit does not tend to any finite value or approaches infinity. Example: The limit of x^2+5 tend to 6 as x approaches -1.
Undefined: You cannot divide by zero
Undefined: You cannot divide by zero