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Melvina Boyle

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14y ago

limx=>05x/(3sin(x)*cos(x)) = 5/3 * limx=>0(x/(sin(x)*cos(x)) = 5/3 * (1/limx=>02x)) = 5/3 * 1/1 = 5/3.

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As a start, you must remove the interdeterminant forms by using the L'Hopital rule:

Deriving the terms, we have:

5/3 * limx=>0(1/(cos2(x) - sin2(x)) = 5/3 * limx=>0(1/cos(2x))

Rule of Continuity:

5/3 * (1/cos(limx=>0(2x)) = 5/3 * 1/(cos(0)) = 5/3 * 1/1 = 5/3.

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Q: What is the limit as x approaches zero of 5x divided by 3sinxcosx?
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