The slope is defined as the ratio of the "rise" divided by the "run" between two points on a line, or in other words, the ratio of the altitude change to the horizontal distance between any two points on the line. Given two points (x1,y1) and (x2,y2) on a line, the slope m of the line is
5x+4y = -3 4y = -5x-3 y = -5/4 x - 3 Slope is -5/4.
First rearrange these simultaneous equations in the form of: 7x-4y = 26 5x-4y = 14 Subtract the bottom equation from the top equation remembering that a - - is equal to a plus. So, -4y - - 4y = 0 2x = 12 and therefore it follows that x = 6 Substitute the value of x into the original equations to find the value of y: Therefore: x = 6 and y = 4
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
If x - 4y = 2 and x + 4y = 2 then the only solution is when y = 0 and thus x = 2.
2x + 6y = 93x - 12y = 15Chose the second equation because you can simplify it.3x - 12y = 15 divide by 3 to both sidesx - 4y = 5 add 4y to both sidesx = 4y + 5Replace 4y + 5 for x to the first equation.2x + 6y = 92(4y + 5) + 6y = 98y + 10 + 6y = 914y = -1y = -1/14x = 4y + 5x = 4(-1/14) + 5x = -2/7 + 5x = -2/7 + 35/7x = 33/7
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5x+4y = -3 4y = -5x-3 y = -5/4 x - 3 Slope is -5/4.
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
q2
== == y = -x + 5
5x+4y = 20 4y = -5x+20 y = -5/4x+5 Therefore: slope is -5/4 and intercept is 5
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
-2x + 4y = -18It's the equation of a straight line with a slope of (1/2) and a y-intercept of (y= -4.5) .
It's the equation of a straight line with a slope of -1.5 and a y-intercept of -3.
-4x + 4y = 1
5x+4y = -4 4y = -5x -4 y = -5/4x -1 or as y = -1.25x -1 both of which are in slope-intercept form
4y-8x+12 = 0 4y = 8x-12 y = 2x-3 The slope is 2 and the y intercept is -3