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What is the specific heat of a substance that absorbs 2.5 x 10 joules of heat when a sample of 1.0 x 10 g of the substance increased in temperature from 10.0c to 70.0 degree c?
Wiki User
∙ 12y ago
Q (heat) = mass*Specific Heat*Temperature difference
I assume 2.5 * 101 Joules? or 25 J & 10 grams of substance?
25 J = 10 grams * (SH) * (70-10oC)
25 J =10 g *60oC * SH
SH = 25 J/(10 g * 60oC)
S.H. = 0.0417 J/gOC
Wiki User
∙ 12y ago
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