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The value of k x l x m x n is the product of all four variables: k, l, m, and n. To find the final value, you would simply multiply the numerical values of k, l, m, and n together. This operation follows the commutative property of multiplication, meaning you can multiply the numbers in any order and still get the same result.
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Find the value of d so that the number n is 26578d341 is divisible by 11?
d = 2(n = 265782341)
What is the relationship between the deggre number of zeros or x intercepts on a graph?
I am not really sure what you are asking for, but any intercept on the x-axis has a y value of 0, so for any particular x value N, the intercept is at (N, 0).
What is the value of n in the equation 3n-8 equals 32-n?
3n-8 = 32-n add n to both sides 4n-8 = 32 add 8 to both sides 4n = 40 divide both sides by 4 n = 10
-the sum of one number and four times another number is 64 Find the value of the numbers so that their product is a maximum?
The numbers are 8 and 32 and the max product is 256.Let one number be mLet the other be nWe have m + 4n = 64So 4n = 64 - mor n = 16- m/4We want mn = m(16 - m/4) to be a max value.That is to say the product of these two numbers equals -(1/4)m2 + 16m.Now depending on you level of math there are many ways to do this.If you know calculus, you can take the derivative of f(m)= -(1/4)m2 + 16mand you find it as -(1/2)m + 16.Now you would set that equal to zero which will indicates m = 32.So you have:-(1/2)m + 16 = 0m = 32To find the other number, substitute 32 for m into the equation n = 16 - m/4 and solve for n.So that the other number is 16-32/4 or 8.Thus, the numbers are 8 and 32, and their product is 256.Since f(m)=16m-m2 /4, we can also look at f(32)= 16(32)-322 /4=512-256=256METHOD TWONow if you don't know calculus, here is another way to do it.You can see that f(m)= -(1/4)m2 + 16m is a quadratic function written in standard form asax2 + bx + c, where a = -1/4, b = 16, and c = 0.The graph is a parabola which opens down since the sign of the coefficient of m2 is negative (a = -1). We need to find the vertex of the parabola where the y-coordinate will be the max value.The formula for the vertex is (-b/2a, f(-b/2a)), so we have-b/2a = -16/(2(-1/4)) = 32, andf(m) = -(1/4)m2 + 16mf(-b/2a) = f(32) = -(1/4)(32)2 + 16(32) = 256Therefore, the vertex of the parabola is at (32, 256) and the maximum value of 256 happens when m = 32. Since this max value is the product of m and n, then n = 8 (256/32).METHOD THREEOnce again look at the function f(m)=16m-m2 /4 and write it in standard formf(m)=-m2 /4 +16mNow complete write this as -1/4(m2 -64m) and complete the square.We havef(m)=-1/4(m -32)2 +256This tells us the graph is a parabola with vertex (32, 256)Since the parabola opens downward, 256 is the max.
When 70,000 is written as 7.0 x 10n what is the value of n?
70,000 can be written as 7.0 x 10^4
