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In order to answer that, I'd need to know how 'x' is related to PRQS.

A little sketch would be a dandy way of presenting that information.

In fact, I'll just bet there's a little sketch right there beside it, in the

place where you got this question from.

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Q: What is the value of x if PRQS is 34?
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Related questions

What is the value of 48 x 34?

1,632


x⁴ + x⁻⁴=34, calculate the highest value of "x"ll?

1.932.


What is the value of 3 to the power of 4?

We know that 34 is 3 x 3 x 3 x 3, and 34 = 81.


Negative 34 plus x equals 6 what do you do?

In equations, this is how to figure it out. -34+ x =6 -34+ x - -34=6- -34 x=40 (subtracting a negative number is actually adding it's absolute value, its distance from 0)


What is the value of 48x34?

48 x 34 = 1632


If EFGH is a parallelogram what is the value of x (4x-2) 34?

Apex 37


What is the value of 567?

The number 567 can also be expressed as 34 x 7.


What is 34 times tables?

1 x 34 = 34 2 x 34 = 68 3 x 34 = 102 4 x 34 = 136 5 x 34 = 170 6 x 34 = 204 7 x 34 = 238 8 x 34 = 272 9 x 34 = 306 10 x 34 = 340 11 x 34 = 374 12 x 34 = 408


What can be multpled and get 34?

Tons of numbers can be multiplied to get 34. 34 x 1 = 34 17 x 2 = 34 10 x 3.4 = 34 8.5 x 4 = 34 4.25 x 8 = 34


What is the value of x in the equation 4x 2 equals 2x 34?

If the missing signs are pluses, x = 16.


What is 34= X - 12?

34 = X - 12 X = 34 + 12 X = 46 We can double check by plugging it into the equation and verifying that it is correct: 34 = 46 - 12


What is the value of x if 5X plus 3Y equals -34?

Since you only have one equation, you will be unable to find a specific number to which x is equal. However, you can put it in terms of y. To do so, isolate the x terms on one side of the equation. This is will give you 5x = -3y - 34. To isolate x, divide everything by 5, which will result in x = -3/5 y - 34/5. That is as simple as you can make it, unless you have a second equation in the same problem, in which case you can take that value of x (-3/5 y - 34/5), plug it into the second equation in place of all the x's, solve for y, and then substitute that value back into the first equation to solve for x.