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x - y = 1 y = x - 1 So any line with slope of 1 would be parallel to the given line. For example, y = x y = x + 3 y = x - 5 etc.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
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Y = 3x - 2This is the equation of a straight line that intercepts the Y axis at -2. It has a gradient of 3/1, meaning that for every unit moved to the right, the line rises three units up the y axis.
A horizontal line crossing the y axis at 3.
A horizontal line, such as Y = 3, has a slope of zero.Slope is the limit, as delta x approaches zero, of delta y / delta x.
the slope of the line y=3 is 0. if you draw the line y=3, you get a straight horizontal line across the 3 on the y axis. Since the line is horizontal and parallel to the x axis, it's slope is 0.
y+3
The graph is a horizontal line at y=3
the slope of the line y=3 is 0. if you draw the line y=3, you get a straight horizontal line across the 3 on the y axis. Since the line is horizontal and parallel to the x axis, it's slope is 0.
If you mean y = -4x+3 then the gradient of the line is -4 and the y intercept is 3
A horizontal line crossing the y axis at 3.
For the line y = 3 , there is no x-intersect., because y = 3 is a parallel line with y- 0 ( the x-axis).
It has the same slope as the line in the question. If a line has equation y = mx + c, its slope is m. If the line in question is y = 5x + 3, the slope of a parallel line is 5; If the line in question is y + 5x = 3 → y = -5x + 3 (subtract 5x from both sides), the slope of a parallel line is -5.
-- a straight line -- the slope of the line is ' 1 ' -- the line passes through the point [y= -3] on the y-axis
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