When a snapper's tail weighs eight kg Its head weighs as much as the tail and one half of the body combined and the body weighs as much as the head and tail combines what does the whole snapper weigh?

Answer 1

Let H = weight of Head
Let T = weight of Tail
Let B = weight of Body

(1) H = T + (1/2)*B (given)

(2) B = H + T (given)

Substituting (2) into (1) gives:

(3) H = T + (1/2) * (H + T)

Reducing (3) by algebra yields:

(4) H = 3 * T

Since it was given that the tail (T) weighs 8 kg, then H = 24 kg.

Then solve (2) to get B = 32kg

So the solution is:
Tail = 8 kg
Head = 24 kg
Body = 32 kg.

So the whole snapper weighs 8+24+32 = 64 kg.