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First, set up the integral W= /int_{0}^{0.12}k*x.

Solve the integral on the right side.

It should lead to W= (9/1250)*k.

Substitute W=1 on the left side and solve for k.

k should equal (1250/9)

Substitute k=(1250/9) and x=0.12 in the equation F=kx and solve for F.

F should equal (50/3).

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Q: Work of 1 Joules is done in stretching a spring from its natural length to 12 cm beyond its natural length what is the force in Newtons that holds the spring stretched at the same distance 12 cm?
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