it equals x1 it equals x1
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Because you are just adding the same variable to itself, the variable does not change. in the same way that 2 + 2 is 4, 2x2 + 2x2 is 4x2.
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
2 9 1 plus 1 is 2.
The expression 2x squared minus x squared simplifies to x squared. This is because when subtracting like terms, you subtract the coefficients while keeping the variable and its exponent the same. In this case, 2x squared minus x squared leaves you with just x squared.
X2 + 3X - 18 Ask yourself, what two factors of - 18 add to 3? (X + 6)(X - 3) -----------------