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2K(s) + 2H2O(l) -> 2KOH(s) +H2(g)

However, if potassium were dropped into water, there would be so much water that the KOH would not be solid but aqueous so it should read

2K(s) + 2H2O(l) -> 2KOH(aq) +H2(g)

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15y ago

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