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Density of HCl = 1.186 g/mL
Molar Mass HCl = 36.46g/mol
We want a concentration in mol/L so we will first convert density into g/L
(1.186 g/mL)(1000mL/1L) = 1186 g/L
We must now know what density 37% of that is
(0.37)(1186 g/L) = 438.82 g/L
Now divide this density by the molar mass to cance out the g and give you mol/L (concentration)
C = (438.82g/L)/(36.46g/mol)
C = 12.04 M
Since HCl is monoprotic, 1M = 1N.
Therefore, 37% HCl is ~12N
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ReneTo convert percent HCl to normality, first divide the percent concentration by the molar mass of HCl to get the molarity. Then, since normality is the number of equivalents of solute per liter of solution, for HCl you would multiply the molarity by 1 (since HCl provides 1 equivalent of H+ ion). So, 37% HCl would be 37/36.5 = 1.01 M HCl, which is equivalent to 1.01 N HCl.
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What is the normality of 37 percent fuming HCl?
To find the normality of a solution, you need to know the molarity and whether the solution is monoprotic or polyprotic. Since fuming HCl is typically monoprotic (one hydrogen per molecule), you can assume the normality is equal to the molarity. Therefore, the normality of a 37% fuming HCl solution is approximately 11.1 N (since 37% is roughly 11.1 M HCl).
How do you prepare 0.5n HCL from 37 percent HCL?
To prepare 0.5N HCl from 37% HCl solution, you can use the formula C1V1 = C2V2 where C1 is the initial concentration, V1 is the initial volume, C2 is the desired concentration (0.5N), and V2 is the final volume. Calculate the volume of 37% HCl needed and dilute it to the desired volume with water.
How do you prepare 0.5M HCL from 37 percent HCL?
To prepare 0.5M HCl from 37% HCl, you would dilute the concentrated HCl with water. Since the concentration of the concentrated HCl is 37%, you can use the formula: (C1V1) = (C2V2) where C1 = concentration of concentrated HCl, V1 = volume of concentrated HCl, C2 = desired concentration of HCl (0.5M), and V2 = final volume (in liters). Solve for V1 to find the volume of concentrated HCl needed. Then, dilute it to the desired volume with water.
Where do you get the 82.81 ml during the preparation of 1 N solution of HCl from a concentrated 37 percent HCl?
To prepare a 1 N solution of HCl from a concentrated 37% HCl solution, you would need to dilute the concentrated solution with water. The calculation to determine the volume of 37% HCl needed to make 1 N solution would be: (1N x 36.46 g/mol HCl) / 0.37 g/ml = 98.65 mL. Since the 37% HCl solution is already at 37%, only 82.81 ml would be needed to make the desired solution strength.
How do you make HCl 5 normal?
To make 5N HCl solution, add the appropriate volume of concentrated hydrochloric acid (usually around 37% concentration) to water to achieve the desired normality. Use proper safety precautions as hydrochloric acid is corrosive and should always be added to water, not the other way around, to avoid splattering. It's recommended to double-check calculations and volumes to ensure accuracy.
