how many mg per ml are are there in a 1% solution? how many mg per ml are there in a 200 ml polyfuser of 8.4% sodium bicarbonate? how much is 15% of 3 litres? you need to give a bolus of 1mg of adrenaline (epinepherine). you have a 1:1000 solution. how much should you give? convert the follwing strengths to percentage. 1g in 25ml 1g in 90ml 1 in 10,000 1 in 750 please coplete the following question how many mg per ml are are there in a 1% solution? how many mg per ml are there in a 200 ml polyfuser of 8.4% sodium bicarbonate? how much is 15% of 3 litres? you need to give a bolus of 1mg of adrenaline (epinepherine). you have a 1:1000 solution. how much should you give? convert the follwing strengths to percentage. 1g in 25ml 1g in 90ml 1 in 10,000 1 in 750 please coplete the following question
To convert percent acid strength into moles, you need to know the molarity of the acid solution. Then, you can use the formula: moles = (percent strength * volume * molarity) / 100 where percent strength is the percentage of acid in the solution, volume is the volume of the solution in liters, and molarity is the concentration of the acid in moles per liter.
No, the equivalence point is not the same as pKa. The equivalence point is the point in a titration where the moles of acid are stoichiometrically equal to the moles of base, while pKa is a measure of the strength of an acid and its tendency to donate a proton.
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
To calculate the excess moles of acid in a titration, subtract the moles of base used from the initial moles of acid. This will give you the amount of acid that was not neutralized by the base and therefore the excess moles of acid present in the solution.
You would need to add 20 ml of 10 percent acid to the 10 ml of 50 percent acid to achieve an average strength of 20 percent acid. This is based on the principle of weighted averages where the final concentration is the average of the individual concentrations weighted by their volumes.
First, calculate the molarity of the sulfuric acid solution using the given mass of sulfuric acid and volume of water. Then, convert the molarity to moles of sulfuric acid. Finally, divide the moles of sulfuric acid by the total moles of all components (sulfuric acid and water) to find the mole fraction of sulfuric acid in the solution.
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No, the equivalence point is not the same as pKa. The equivalence point is the point in a titration where the moles of acid are stoichiometrically equal to the moles of base, while pKa is a measure of the strength of an acid and its tendency to donate a proton.
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
To determine the number of moles of formic acid in 25 grams of acetic acid, you first need to convert the mass of acetic acid to moles. The molar mass of acetic acid is about 60 g/mol. Then, use the molar ratio between formic acid and acetic acid (1:1) to calculate the number of moles of formic acid.
To calculate the excess moles of acid in a titration, subtract the moles of base used from the initial moles of acid. This will give you the amount of acid that was not neutralized by the base and therefore the excess moles of acid present in the solution.
You would need to add 20 ml of 10 percent acid to the 10 ml of 50 percent acid to achieve an average strength of 20 percent acid. This is based on the principle of weighted averages where the final concentration is the average of the individual concentrations weighted by their volumes.
The molecular formula for carbonic acid is H2CO3. To find the mass of carbonic acid formed, first calculate the moles of carbon and water. Then, determine the limiting reactant and use it to calculate the moles of carbonic acid formed. Finally, convert the moles of carbonic acid to grams to find the mass.
First, calculate the molarity of the sulfuric acid solution using the given mass of sulfuric acid and volume of water. Then, convert the molarity to moles of sulfuric acid. Finally, divide the moles of sulfuric acid by the total moles of all components (sulfuric acid and water) to find the mole fraction of sulfuric acid in the solution.
To find the molarity, first convert the mass of sulfuric acid to moles by dividing by its molar mass (98.08 g/mol). Then, calculate the molarity by dividing the moles of sulfuric acid by the volume of the solution in liters (280 mL = 0.28 L). Molarity = moles of solute / liters of solution.
In hydrochloric acid (HCl), there is one mole of chlorine for every mole of hydrochloric acid. Therefore, in 3.4 moles of hydrochloric acid, there are also 3.4 moles of chlorine.
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
You can convert pH to Percent dissociated easily using the Ka value. You can calculate the [H+] from the pH value, the [A-] from stoichiometry, and the [HA] from all of the above. It is easy to find the percent dissociation from here.