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how many mg per ml are are there in a 1% solution? how many mg per ml are there in a 200 ml polyfuser of 8.4% sodium bicarbonate? how much is 15% of 3 litres? you need to give a bolus of 1mg of adrenaline (epinepherine). you have a 1:1000 solution. how much should you give? convert the follwing strengths to percentage. 1g in 25ml 1g in 90ml 1 in 10,000 1 in 750 please coplete the following question how many mg per ml are are there in a 1% solution? how many mg per ml are there in a 200 ml polyfuser of 8.4% sodium bicarbonate? how much is 15% of 3 litres? you need to give a bolus of 1mg of adrenaline (epinepherine). you have a 1:1000 solution. how much should you give? convert the follwing strengths to percentage. 1g in 25ml 1g in 90ml 1 in 10,000 1 in 750 please coplete the following question

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To convert percent acid strength into moles, you need to know the molarity of the acid solution. Then, you can use the formula: moles = (percent strength * volume * molarity) / 100 where percent strength is the percentage of acid in the solution, volume is the volume of the solution in liters, and molarity is the concentration of the acid in moles per liter.

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Q: How do you convert percent acid strength into moles?
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Is equivalence point PKa?

No, the equivalence point is not the same as pKa. The equivalence point is the point in a titration where the moles of acid are stoichiometrically equal to the moles of base, while pKa is a measure of the strength of an acid and its tendency to donate a proton.


What weight of nitric acid can be produced from 18.5 gram of nitrogen dioxide?

To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.


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To calculate the excess moles of acid in a titration, subtract the moles of base used from the initial moles of acid. This will give you the amount of acid that was not neutralized by the base and therefore the excess moles of acid present in the solution.


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In hydrochloric acid (HCl), there is one mole of chlorine for every mole of hydrochloric acid. Therefore, in 3.4 moles of hydrochloric acid, there are also 3.4 moles of chlorine.


What is the mole fraction of sulfuric acid in a solution made by adding 3.4 grams of sulfuric acid to 3500 mL of water?

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