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how many mg per ml are are there in a 1% solution? how many mg per ml are there in a 200 ml polyfuser of 8.4% sodium bicarbonate? how much is 15% of 3 litres? you need to give a bolus of 1mg of adrenaline (epinepherine). you have a 1:1000 solution. how much should you give? convert the follwing strengths to percentage. 1g in 25ml 1g in 90ml 1 in 10,000 1 in 750 please coplete the following question how many mg per ml are are there in a 1% solution? how many mg per ml are there in a 200 ml polyfuser of 8.4% sodium bicarbonate? how much is 15% of 3 litres? you need to give a bolus of 1mg of adrenaline (epinepherine). you have a 1:1000 solution. how much should you give? convert the follwing strengths to percentage. 1g in 25ml 1g in 90ml 1 in 10,000 1 in 750 please coplete the following question
What else can I help you with?
Is equivalence point PKa?
No, the equivalence point is not the same as pKa. The equivalence point is the point in a titration where the moles of acid are stoichiometrically equal to the moles of base, while pKa is a measure of the strength of an acid and its tendency to donate a proton.
What weight of nitric acid can be produced from 18.5 gram of nitrogen dioxide?
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
How to calculate excess moles of acid in titration?
To calculate the excess moles of acid in a titration, subtract the moles of base used from the initial moles of acid. This will give you the amount of acid that was not neutralized by the base and therefore the excess moles of acid present in the solution.
How many moles of chlorine are in 3.4 moles of hydrolic acid?
In hydrochloric acid (HCl), there is one mole of chlorine for every mole of hydrochloric acid. Therefore, in 3.4 moles of hydrochloric acid, there are also 3.4 moles of chlorine.
What is the mole fraction of sulfuric acid in a solution made by adding 3.4 grams of sulfuric acid to 3500 mL of water?
The mole fraction must be calculated in moles solvent over moles solution. So, 3.4 grams sulfuric acid equals .0347 moles sulfuric acid. 3500 mL water equals 3500 g water equals 194 mols. .0347 mols/(.0347+194) = 1/5591.77 mols/mol
How do you determine the no of moles of water if strength of hydrated and anhydrous samples of oxalic acid is given?
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How many moles of formic acid is there in 25 grams of acetic acid?
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
Is equivalence point PKa?
No, the equivalence point is not the same as pKa. The equivalence point is the point in a titration where the moles of acid are stoichiometrically equal to the moles of base, while pKa is a measure of the strength of an acid and its tendency to donate a proton.
What weight of nitric acid can be produced from 18.5 gram of nitrogen dioxide?
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
How to calculate excess moles of acid in titration?
To calculate the excess moles of acid in a titration, subtract the moles of base used from the initial moles of acid. This will give you the amount of acid that was not neutralized by the base and therefore the excess moles of acid present in the solution.
If 44 grams of carbon react completely with 18 grams of water what is the mass of carbonic acid formed?
The molecular formula for carbonic acid is H2CO3. To find the mass of carbonic acid formed, first calculate the moles of carbon and water. Then, determine the limiting reactant and use it to calculate the moles of carbonic acid formed. Finally, convert the moles of carbonic acid to grams to find the mass.
How many moles of chlorine are in 3.4 moles of hydrolic acid?
In hydrochloric acid (HCl), there is one mole of chlorine for every mole of hydrochloric acid. Therefore, in 3.4 moles of hydrochloric acid, there are also 3.4 moles of chlorine.
What is the mole fraction of sulfuric acid in a solution made by adding 3.4 grams of sulfuric acid to 3500 mL of water?
The mole fraction must be calculated in moles solvent over moles solution. So, 3.4 grams sulfuric acid equals .0347 moles sulfuric acid. 3500 mL water equals 3500 g water equals 194 mols. .0347 mols/(.0347+194) = 1/5591.77 mols/mol
What is the molarity of 70 grams of sulfuric acid in 280 mL solution.?
To find the molarity, first convert the mass of sulfuric acid to moles by dividing by its molar mass (98.08 g/mol). Then, calculate the molarity by dividing the moles of sulfuric acid by the volume of the solution in liters (280 mL = 0.28 L). Molarity = moles of solute / liters of solution.
What strength of 20 ml acid should be added to 10 ml of 50 percent acid to get an average strength of 20 percent acid?
The formula is M1V1 + M2V2 = MtVt You know V1, M2, V2, Mt and Vt and the units all match, so simply plug the numbers in and solve: M1(20) + (50)(10) = (20)(30) 20M1 + 500 = 600 20M1 = 100 M1 = 5 You should add 20 ml of 5% acid to 10 ml of 50% acid to get an acid strength of 20%.
How many moles of stomach acid would be neutralized by one tablet of regular strength maalox that contains 600 mg of calcium carbonate?
To calculate the number of moles of stomach acid neutralized by calcium carbonate, you first need to convert the mass of calcium carbonate (600 mg) to grams (0.6 g). Then, use the molar mass of calcium carbonate (100.09 g/mol) to find the number of moles. Finally, use the balanced chemical equation to determine the moles of stomach acid neutralized.
How many moles of H are in 0.75 moles of H2SO4?
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
