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What do you deduce from the volume ratio about the mole ratio in which lead nitrate and sodium iodide react?
Since the volume ratio of two gases in a chemical reaction is directly proportional to the mole ratio of the reactants, you can infer that the mole ratio of lead nitrate to sodium iodide in their reaction is the same as the volume ratio of the gases involved. This allows you to determine the stoichiometry of the reaction.
What else can I help you with?
How do you calculate the volume in milliliters of a 0.61M sodium nitrate solution that contains 400mmol of sodium nitrate?
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.
What is the procedure for the standardization of sodium thiosulfate?
To standardize sodium thiosulfate, first, prepare a known concentration of iodine solution using potassium iodide and iodine. Titrate this iodine solution with the sodium thiosulfate solution until a color change is observed. The volume of sodium thiosulfate used can then be used to calculate the exact concentration of the solution.
What is the volume of 24 mmol of ethyl iodide and the theoretical yield of p-ethoxynitrobenzene?
The volume of 24 mmol of ethyl iodide would depend on its density, which is about 2.29 g/cm³. To calculate the volume, you would need to convert 24 mmol to grams using the molar mass of ethyl iodide (155.99 g/mol) and then divide by the density. The theoretical yield of p-ethoxynitrobenzene would depend on the reaction conditions and stoichiometry of the reaction involving ethyl iodide, but you would use the molar ratio of ethyl iodide to p-ethoxynitrobenzene to calculate the theoretical yield.
What is the molarity of a solution in which 0.45 grams of sodium nitrate are dissolved in 265 mL of solution?
To calculate the molarity, first convert the mass of sodium nitrate to moles using its molar mass. Then, divide the number of moles by the volume of solution in liters (265 mL = 0.265 L) to get the molarity. The molarity of the solution is about 0.68 M.
How do you prepare 1millimolar silver nitrate solution from 0.5 molar silver nitrate?
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
How do you calculate the volume in milliliters of a 0.61M sodium nitrate solution that contains 400mmol of sodium nitrate?
By definition, a 0.61M sodium nitrate solution contains 0.61 moles of sodium nitrate per liter, which is equivalent to 0.61 mmol/ml. Therefore, the volume of this solution required to contain 400mmol is 400/0.61 or 6.6 X 102 ml, to the justified number of significant digits.
How do you prepare 1000 ppm nitrate solution from sodium nitrate?
To prepare a 1000 ppm nitrate solution from sodium nitrate, you would dissolve a specific amount of sodium nitrate in a known volume of water. For example, to prepare 1 liter of a 1000 ppm nitrate solution, you would dissolve 1 gram of sodium nitrate in 1 liter of water. Make sure to accurately weigh the sodium nitrate and dissolve it completely in the water to achieve the desired concentration.
What is the volume of 24 mol of ethyl iodide and the theoretical yield of p-ethoxynitrobenzene?
The volume of 24 mol of ethyl iodide is 1,929 L.
What is the procedure for the standardization of sodium thiosulfate?
To standardize sodium thiosulfate, first, prepare a known concentration of iodine solution using potassium iodide and iodine. Titrate this iodine solution with the sodium thiosulfate solution until a color change is observed. The volume of sodium thiosulfate used can then be used to calculate the exact concentration of the solution.
Equal volumes of 0.120molL potassium nitrate and 0.160molL ironiiinitrate are mixed together What is the concentration of nitrate ions in the mixture?
To find the concentration of nitrate ions in the mixture, we first calculate the moles of nitrate ions from each salt using the formula moles = concentration x volume. For potassium nitrate: 0.120 mol/L x volume = moles of nitrate ions. For iron (II) nitrate: 0.160 mol/L x volume = moles of nitrate ions. Add the moles of nitrate ions from both salts to get the total moles of nitrate ions in the mixture. Finally, divide the total moles of nitrate ions by the total volume of the mixture to get the concentration of nitrate ions in the mixture.
What is the volume of 24 mmol of ethyl iodide and the theoretical yield of p-ethoxynitrobenzene?
The volume of 24 mmol of ethyl iodide would depend on its density, which is about 2.29 g/cm³. To calculate the volume, you would need to convert 24 mmol to grams using the molar mass of ethyl iodide (155.99 g/mol) and then divide by the density. The theoretical yield of p-ethoxynitrobenzene would depend on the reaction conditions and stoichiometry of the reaction involving ethyl iodide, but you would use the molar ratio of ethyl iodide to p-ethoxynitrobenzene to calculate the theoretical yield.
What is the molarity of a solution in which 0.45 grams of sodium nitrate are dissolved in 265 mL of solution?
To calculate the molarity, first convert the mass of sodium nitrate to moles using its molar mass. Then, divide the number of moles by the volume of solution in liters (265 mL = 0.265 L) to get the molarity. The molarity of the solution is about 0.68 M.
What is the volume of 35.7g of sodium chloride in 100cm3 of cold water?
What is the volume of 35.7g of sodium chloride in 100cm3 of cold water?
How do you prepare 1millimolar silver nitrate solution from 0.5 molar silver nitrate?
Dilute 1 mL of 0.5 M silver nitrate solution to a total volume of 1 L with water to make a 1 mM silver nitrate solution.
What is the volume of 30 g of sodium?
To determine the volume of 30 g of sodium, you would need to know the density of sodium. Sodium has a density of 0.97 g/cm³ at room temperature. Using the density, you can calculate the volume of 30 g of sodium by dividing the mass (30 g) by the density (0.97 g/cm³). This would give you the volume in cubic centimeters (cm³).
What is the relationship between the mass and volume of a sodium chloride solution?
Density=Mass/Volume
What volume of 5.19M sodium chloride contains 250 moles of sodium chloride?
The answer is 48,17 L.
