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This should be SO4-2 ion. sulfur shows +6 in this ion.
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What is the oxidation numbers for SO4?
In the sulfate ion (SO4^2-), the oxidation number of sulfur (S) is +6, while the oxidation number of each of the four oxygen (O) atoms is -2.
What is the oxidation number of (nh4)2ce(so4)3?
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
The oxidation number of sulfur in H2 SO4 is?
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
What is the oxidation number of SO4?
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
What is the oxidation state of an individual sulfur atom in SO4?
The oxidation state of an individual sulfur atom in SO4 is +6. In the sulfate ion (SO4^2-), each oxygen atom has an oxidation state of -2, for a total of -8. Since the overall charge of the sulfate ion is -2, the sulfur atom must have an oxidation state of +6 to balance out the charge.
