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This should be SO4-2 ion. sulfur shows +6 in this ion.
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What is the oxidation numbers for SO4?
This should be SO4-2 ion. sulfur shows +6 in this ion.
What is the oxidation number of (nh4)2ce(so4)3?
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
The oxidation number of sulfur in H2 SO4 is?
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
What is the oxidation number of SO4?
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
What is the oxidation state of an individual sulfur atom in SO4?
The oxidation state of an individual sulfur atom in SO4 is +6. In the sulfate ion (SO4^2-), each oxygen atom has an oxidation state of -2, for a total of -8. Since the overall charge of the sulfate ion is -2, the sulfur atom must have an oxidation state of +6 to balance out the charge.
What is the oxidation numbers for SO4?
This should be SO4-2 ion. sulfur shows +6 in this ion.
What is the oxidation number of (nh4)2ce(so4)3?
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
The oxidation number of sulfur in H2 SO4 is?
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
What is the oxidation number of SO4?
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
What is the oxidation state of an individual sulfur atom in SO4?
The oxidation state of an individual sulfur atom in SO4 is +6. In the sulfate ion (SO4^2-), each oxygen atom has an oxidation state of -2, for a total of -8. Since the overall charge of the sulfate ion is -2, the sulfur atom must have an oxidation state of +6 to balance out the charge.
What is the oxidation number of O in SO4?
Oxygen atoms are generally considered to have an oxidation number of -2 in all oxyanions such as sulfate.
What is the oxidation state of ZnSO4?
In ZnSO4, the oxidation state of Zn (Zinc) is +2, the oxidation state of sulfur (S) is +6, and the oxidation state of oxygen (O) is -2. This is because the overall charge of the compound is zero, so the sum of the oxidation states must equal zero.
What is the oxidation state of an individual sulfur atom in SO42-?
The oxidation state of sulfur in SO4^2- is +6. This is because oxygen typically has an oxidation state of -2, and there are 4 oxygen atoms in SO4^2-. Since the overall charge of the ion is -2, the oxidation state of sulfur must be +6 to balance the charges.
What is the oxidation state of each element in (SO4)2-?
SO4^2- has a net negative 2 charge.each O = 2-S = 6+
What is the oxidation number of Cr in Cr2(SO4)3?
The oxidation number of chromium (Cr) in Cr2(SO4)3 is +3. This is because the overall charge of the sulfate ion (SO4) is -2, and there are a total of 3 sulfate ions present in the compound, requiring the chromium to have an oxidation state of +3 to balance the charges.
What is the oxidation number of Ca So4?
Since the SO4-2 ions have two negative charges and oxygen atoms in almost all compounds have two negative charges each, the sulfur atoms have an oxidation number of -2 -4(-2) = +6.
What is the oxidation state of SO42?
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-
