0
You know that there are 12 items in a dozen. No matter what the item, a dozen is equal to 12. A gross is another unit of grouping. There are 144 items in a gross. A score, another set group, is equal to 20 items. You can have a score of years or a score of rocks, but it will always be 20 items. Now, a mole is a unit of grouping, just like these examples. The only difference is that a mole represents a large number of items, 602 000 000 000 000 000 000 000 (or 6.02 x 1023) items to be more specific. What the items are doesn't matter. You can have a mole of molecules, a mole of ions, or a mole of stars. The number of items in a mole will always be 6.02 x 1023 . This number is known as Avogadro's number.
Still curious? Ask our experts.
Chat with our AI personalities
Judy
Ezra
Jordan6.023 x 10 to the power of 23 is the number of Atoms in a Mole (A mole is the amount of a substance that contains the same number of units of atoms or molecules or ions, as there are atoms in 12 g of Carbon)
6.023 x 10 to the power of 23 is called Avogadro's Number.
For more information see http://www.tutorvista.com/content/chemistry/chemistry-ii/stoichiometry/mole-concept.php
Add your answer:
Earn +20 pts
How many moles of gold are in 1.20 times 10 to the 24th atoms of gold?
To find the number of moles of gold, we need to divide the number of atoms by Avogadro's number. Avogadro's number is approximately 6.022 x 10^23/mol, so in this case, 1.20 x 10^24 atoms divided by 6.022 x 10^23/mol gives approximately 1.99 moles of gold.
How many atoms of gold in one mole of gold?
In one mole of gold, there are 6.022 x 10^23 atoms of gold. This number represents Avogadro's constant, which is the number of atoms, ions, or molecules in one mole of a substance.
At saturation 8.5 x 10-4 moles of Ag2CO3 have dissolved in 1 liter of water What is Ksp for Ag2CO3 at this temperature?
The solubility product constant (Ksp) can be calculated using the formula: Ksp = [Ag+]^2 [CO3^2-]. Since 1 mole of Ag2CO3 dissolves to form 2 moles of Ag+ and 1 mole of CO3^2-, at saturation, the concentration of Ag+ and CO3^2- ions would be 2 * 8.5 x 10^-4 moles/L and 8.5 x 10^-4 moles/L, respectively. Substituting these values into the Ksp formula gives Ksp = (2 * 8.5 x 10^-4)^2 * (8.5 x 10^-4) = 1.085 x 10^-11.
What is the volume of a salt crystal measuring 2.44 x 10-2 m by 1.4 x 10-3m by 8.4 x 10?
The volume of the salt crystal is calculated by multiplying the three dimensions together: V = (2.44 x 10^-2 m) * (1.4 x 10^-3 m) * (8.4 x 10^-3 m) = 2.85 x 10^-7 m^3.
An acid has Ka equals 3.1 x 10-10 What is the Kb for the conjugate base of this acid at 25 C?
To find the Kb of the conjugate base, you can use the relationship Kw = Ka * Kb. At 25°C, the value of Kw is 1.0 x 10^-14. Given Ka = 3.1 x 10^-10, you can solve for Kb using Kb = Kw / Ka. This gives you Kb = 1.0 x 10^-14 / 3.1 x 10^-10 = 3.23 x 10^-5.
