You know that there are 12 items in a dozen. No matter what the item, a dozen is equal to 12. A gross is another unit of grouping. There are 144 items in a gross. A score, another set group, is equal to 20 items. You can have a score of years or a score of rocks, but it will always be 20 items. Now, a mole is a unit of grouping, just like these examples. The only difference is that a mole represents a large number of items, 602 000 000 000 000 000 000 000 (or 6.02 x 1023) items to be more specific. What the items are doesn't matter. You can have a mole of molecules, a mole of ions, or a mole of stars. The number of items in a mole will always be 6.02 x 1023 . This number is known as Avogadro's number.
6.023 x 10 to the power of 23 is the number of Atoms in a Mole (A mole is the amount of a substance that contains the same number of units of atoms or molecules or ions, as there are atoms in 12 g of Carbon)
6.023 x 10 to the power of 23 is called Avogadro's Number.
For more information see http://www.tutorvista.com/content/chemistry/chemistry-ii/stoichiometry/mole-concept.php
To find the number of moles of gold, we need to divide the number of atoms by Avogadro's number. Avogadro's number is approximately 6.022 x 10^23/mol, so in this case, 1.20 x 10^24 atoms divided by 6.022 x 10^23/mol gives approximately 1.99 moles of gold.
In one mole of gold, there are 6.022 x 10^23 atoms of gold. This number represents Avogadro's constant, which is the number of atoms, ions, or molecules in one mole of a substance.
The solubility product constant (Ksp) can be calculated using the formula: Ksp = [Ag+]^2 [CO3^2-]. Since 1 mole of Ag2CO3 dissolves to form 2 moles of Ag+ and 1 mole of CO3^2-, at saturation, the concentration of Ag+ and CO3^2- ions would be 2 * 8.5 x 10^-4 moles/L and 8.5 x 10^-4 moles/L, respectively. Substituting these values into the Ksp formula gives Ksp = (2 * 8.5 x 10^-4)^2 * (8.5 x 10^-4) = 1.085 x 10^-11.
The volume of the salt crystal is calculated by multiplying the three dimensions together: V = (2.44 x 10^-2 m) * (1.4 x 10^-3 m) * (8.4 x 10^-3 m) = 2.85 x 10^-7 m^3.
To find the Kb of the conjugate base, you can use the relationship Kw = Ka * Kb. At 25°C, the value of Kw is 1.0 x 10^-14. Given Ka = 3.1 x 10^-10, you can solve for Kb using Kb = Kw / Ka. This gives you Kb = 1.0 x 10^-14 / 3.1 x 10^-10 = 3.23 x 10^-5.
602 = (6 x 100) + (0 x 10) + (2 x 1)
6.02 x 10^2
327,000,000,000,000,000,000,000
602,000,000,000,000,000,000,000
602 = 6.02 x 10^2
602,000,000,000,000,000,000,000
You have a few choices:1 x 602 x 303 x 204 x 155 x 126 x 10
8.859 x 10-24 feet
541198
2 x 7 x 43
50.1667
6 + 1,800 = 1,806