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What is the empirical formula for a substance containing 65.95 percent barium and 34.05 percent chlorine?
Wiki User
∙ 11y ago
BaCl2
Wiki User
∙ 11y ago
The empirical formula for a substance containing 65.95% barium and 34.05% chlorine would be BaCl2 (barium chloride). This is determined by converting the mass percentage of each element to moles, finding the ratio of moles of each element, and simplifying to the simplest whole-number ratio.
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What is the empirical formula of 7.8 percent carbon and 92.2 percent chlorine?
The empirical formula of a compound containing 7.8% carbon and 92.2% chlorine is CCl3. This can be determined by converting the percentages to moles, finding the ratio of moles, and simplifying to the smallest whole number ratio.
What is the empirical formula of a molecule containing 24 carbon 6 hydrogen and 70 chlorine?
The empirical formula of the molecule is CHCl₂. This is obtained by dividing the number of atoms of each element by their greatest common factor, leading to a ratio of 1 carbon, 1 hydrogen, and 2 chlorine atoms.
Can one substance have same empirical and molecular formula?
Yes, it is possible for a substance to have the same empirical and molecular formula. This can occur when the substance is composed of only one type of element, such as oxygen gas (O2), where both the empirical and molecular formula are O2.
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What is the empirical formula for boron trichloride?
The empirical formula for boron trichloride is BCl3, as it consists of one boron atom and three chlorine atoms.
What is the empirical formula for Cl and you?
chlorine
What is the empirical formula of 7.8 percent carbon and 92.2 percent chlorine?
The empirical formula of a compound containing 7.8% carbon and 92.2% chlorine is CCl3. This can be determined by converting the percentages to moles, finding the ratio of moles, and simplifying to the smallest whole number ratio.
What is the empirical formula of a molecule containing 24 carbon 6 hydrogen and 70 chlorine?
The empirical formula of the molecule is CHCl₂. This is obtained by dividing the number of atoms of each element by their greatest common factor, leading to a ratio of 1 carbon, 1 hydrogen, and 2 chlorine atoms.
Can one substance have same empirical and molecular formula?
Yes, it is possible for a substance to have the same empirical and molecular formula. This can occur when the substance is composed of only one type of element, such as oxygen gas (O2), where both the empirical and molecular formula are O2.
What is empirical formula of chlorine and Iodine?
Chlorine and iodine are both elements that form diatomic molecules (molecules that consist of two atoms). One atom of chlorine is symbolised by Cl; however, single atoms of chlorine do not exist unattached to other atoms. One molecule of chlorine is Cl2. The situation is the somewhat similar for iodine, and a molecule of iodine is I2. Please see the links.
What is the empirical formula for the molecule?
An empirical formula is a chemical formula containing only the number of atoms why is formed (ex.: C6H12), without any indication about the structure.
What is an empirical formula for the molecule?
An empirical formula is a chemical formula containing only the number of atoms why is formed (ex.: C6H12), without any indication about the structure.
Can you determine the molecular formula of a substance from its percent composition?
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What is the empirical formula for boron trichloride?
The empirical formula for boron trichloride is BCl3, as it consists of one boron atom and three chlorine atoms.
What is the empirical formula for a molecule containing 46.8 Is and 53.2 O?
Si2O3
What is the empirical formula if a 100.0 g sample of a compound is composed of 16.3 g of carbon 32.1 g of chlorine and 51.6 g of fluorine?
To find the empirical formula, convert the masses of each element to moles. The molar ratio of carbon to chlorine to fluorine is 1:1:2. Therefore, the empirical formula is CClF2.
