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What is the empirical formula of a compound that contains 69.24 percent gallium and 30.76 percent phosphorus?
Tha gram Atomic Mass of gallium is 69.723 and the gram atomic mass of phosphorus is 30.9738. 69.24/69.723 is 0.9931 to the justified number of significant digits, while 30.76/30.9738 is also 0.9931 to the justified number of significant digits. These two quotients have as their nearest small whole number ratios 1:1; therefore, the empirical formula of the compound is GaP. This accords with the expectation from the fact that gallium is in wide form Periodic Table column 13 with three valence electrons and phosphorus is in wide form periodic table column 15 with 5 valence electrons. A gallium atom can donate three electrons to a phosphorus atom, resulting in both ions having completely filled outer electron shells.
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A compound formed of only phosphorus and oxygen is found to be 56.35 phosphorus. What is the empirical formula of the compound?
P underscore 2 O underscore 3
What is the empirical formula for K3PO4?
The empirical formula for K3PO4 is K3PO4 itself. This is because the subscripts in the formula (3 for potassium, 1 for phosphorus, and 4 for oxygen) represent the simplest whole-number ratio of the elements in the compound.
How do you write the formula for tetra phosphorus tri sulfide?
The formula for tetraphosphorus trisulfide is P4S3. This compound contains 4 phosphorus atoms and 3 sulfur atoms, thus the formula reflects the ratio of elements in the compound.
What is the empirical formula for a compound whose molecular formula is C2Cl6?
The empirical formula for a compound is the simplest whole number ratio of the elements present in the compound. In this case, the empirical formula for a compound with a molecular formula of C2Cl6 is CH3Cl.
Is phosphorous acid an element?
The empirical formula for phosphoric acid is H3PO4. Its molecular formula is P2O5·3H2O. It is composed of the elements hydrogen, phosphorus and oxygen. Most solutions of phosphoric acid are composed of some amount of H3PO4 in water, H2O.For more information about phosphoric acid, see the Web Links to the left.
What is the empirical formula of the phosphorus bromide?
The empirical formula of phosphorus bromide is PB3. This is derived by finding the simplest whole-number ratio of atoms in the compound.
A compound formed of only phosphorus and oxygen is found to be 56.35 phosphorus. What is the empirical formula of the compound?
P underscore 2 O underscore 3
What is the empirical formula of the phosphorus selenide?
The empirical formula of phosphorus selenide is P2Se3.
What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?
p2o5
Empirical formula for silver oxide?
Silver oxide is an ionic compound so its molecular and empirical formula is same Ag2O
What is the empirical formula for K3PO4?
The empirical formula for K3PO4 is K3PO4 itself. This is because the subscripts in the formula (3 for potassium, 1 for phosphorus, and 4 for oxygen) represent the simplest whole-number ratio of the elements in the compound.
What is the compound formula for phosphorus tribromide?
The compound formula for phosphorus tribromide is PBr3.
How do you know if a formula is an empirical formula?
An empirical formula has no data about the structure of a compound.
What is the empirical formula of a compound that contains 20 percent calcium and 80 percent bromine by mass?
The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.
How do you write the formula for tetra phosphorus tri sulfide?
The formula for tetraphosphorus trisulfide is P4S3. This compound contains 4 phosphorus atoms and 3 sulfur atoms, thus the formula reflects the ratio of elements in the compound.
The lowest whole number ratio of the elements in a compound is called the?
An empirical formula refers to the chemical formula that indicates the simplest ratio of atoms in a compound. Two different compounds may have the same empirical formula.
A compound contains 21.2%N 6.1%H 24.2% and 48.5%O What is it’s empirical formula?
The empirical formula of a compound that consists of 21.2%N, 6.1%H, 24.2% S and 48.5% O is N2H8SO4.
