Wiki User
∙ 9y agoThe mole fraction of HCl is 0.34.
Wiki User
∙ 9y agoTo find the mole fraction of HCl in the solution, we first need to calculate the molar mass of HCl (H=1g/mol, Cl=35.5g/mol). Then, determine the number of moles of HCl in 100g of the solution. Finally, calculate the mole fraction of HCl by dividing the moles of HCl by the total moles of solute and solvent in the solution.
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
You can determine the number of grams of an active ingredient in a solution by multiplying the percent strength of the solution by the total weight or volume of the solution. This will give you the weight of the active ingredient present in the solution.
The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.
A 50% NaOH aqueous solution means that the solution contains 50% sodium hydroxide (NaOH) by weight and the rest is water. This concentration indicates that for every 100 grams of the solution, 50 grams is NaOH.
To make a 10 percent aqueous solution of potassium hydroxide, you would dissolve 10 grams of potassium hydroxide in enough water to make a total solution volume of 100 mL. This solution would be considered a 10 percent concentration by weight. Be cautious when handling potassium hydroxide as it is a caustic substance.
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
To make a 1% aqueous solution of potassium hydroxide, you would mix 1 gram of potassium hydroxide with 99 grams of water (for a total of 100 grams solution). This would give you a solution where 1% of the total weight is potassium hydroxide.
You will have to assume that the 2 % is a volume fraction, then the volume of copper sulfate in the solution would be 11.5 milliliter(575 ml*(0.02). If it were a weight fraction, then you would have to have more information on the solution density.
Multiply the mass fraction by 100.
The weight percent of a caffeine solution made by dissolving 8.35 g of caffeine in 75 g of benzene is calculated as: Weight percent = (mass of caffeine / total mass of solution) * 100 Weight percent = (8.35 g / (8.35 g + 75 g)) * 100 Weight percent ≈ 10.0%
4.00% (percent) by mass (weight) means 4.00g for each 100g of solution. There are 2 x 100g of water, so 2 x 4g =8.00g of NaOH (sodium hydroxide) But, a 4% aqueous solution of NaOH should mean it's 96% (96g) water. There are 2.08333 x 96g of water, so 2.08333 x 4g = 8.33g of NaOH.
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
The weight of 10 percent acetic acid solution would depend on the total volume of the solution. For example, if you have 100 grams of a 10 percent acetic acid solution, it would contain 10 grams of acetic acid.
A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.
To make a percent sucrose solution, dissolve a specific weight of sucrose in a specific volume of water. For example, to make a 10% sucrose solution, dissolve 10 grams of sucrose in 90 mL of water. The formula to calculate the amount of sucrose needed is: (percent sucrose/100) x volume of solution = weight of sucrose (in grams).