62.1%
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
Acetone's has the formula C3H6O. The elements that makeup this organic compound are hydrogen, carbon, and oxygen. Acetone also is called propanone.
To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.
acetone: (CH3)2CO Please see the link.
The acetone molecule has a molecular weight of 58.08 g/mol and a molecular formula of C3H6O, which consists of 3 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom. The actual size of the molecule would depend on its structure and arrangement of atoms in its three-dimensional space.
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
Acetone's has the formula C3H6O. The elements that makeup this organic compound are hydrogen, carbon, and oxygen. Acetone also is called propanone.
To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.
acetone: (CH3)2CO Please see the link.
The acetone molecule has a molecular weight of 58.08 g/mol and a molecular formula of C3H6O, which consists of 3 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom. The actual size of the molecule would depend on its structure and arrangement of atoms in its three-dimensional space.
To write a balanced equation for acetone (C3H6O), you would typically need to react it with another chemical compound. For example, if you were to react acetone with oxygen (O2), the balanced equation would be: 2 C3H6O + 9 O2 → 6 CO2 + 6 H2O
1. Acetone 2. Propanol 3. Cyclopropanol 4. 1-hyrdoxy-1-propene 5. 2-hydroxy-1-propene 6. 2-propanol
At zero degrees Celsius, C3H6O (acetone) would typically be in a liquid state. It has a boiling point of around 56 degrees Celsius and usually remains in a liquid state at room temperature.
I believe you're talking about acetone..... Well, the formula is C3H6O. C stands for Carbon, H for Hydrogen and O for Oxygen. The subscripts refer to the number of atoms of each element in a single molecule of acetone. http://en.wikipedia.org/wiki/Acetone
Acetone consists of carbon, hydrogen, and oxygen atoms. The chemical formula for acetone is C3H6O.
Methanol and acetone are miscible but they doesn't react. Dear (who had asked the question), I just would like to remind the basics: 1. If there is a reaction then there should be a product. 2. Only then you can balance an equation on both sides of 3. Before you put a question, please go through the basics. 4. Did you mean Azeotropic distillation for this mixture?
C3H6O is a compound. It is the chemical formula for acetone, a common organic solvent and household chemical. It is made up of carbon, hydrogen, and oxygen atoms bonded together in a specific arrangement.