It will immensely cost to totally remove the impurities in sulfuric acid. For industrial purposes, they maintain a percentage value around 98%.
The percent ionization of ammonia depends on the concentration and the dissociation constant of the substance. Can you please provide the concentration for a more accurate calculation?
As you increase the concentration of the solution, the concentration of H+ does not change. Meaning, the concentration ionized does not change. Just the original concentration increases. Since percent ionization = (concentration ionized)/(original concentration) , and the original concentration is increased, the percent ionization therefore decreases.
Well if you have 99% solution of H2SO4, that means of one L you have 990 mL the acid. The density of sulphuric acid is 1.84g/mL... so that means you will have by mass 1821.6g of acid. The molecular weigth of H2SO4 is 98.1g/mol... so if you divide mass by molar mass you should get moles... which is about... 18.57moles. So that means 99% sulphuric acid is approx. 19M.
To calculate the concentration of a stock solution, divide the amount of solute by the volume of solvent, and then multiply by 100 to get the concentration in percent.
To find the molarity of a solution with a percent concentration of a solute, you need to know the molecular weight of the solute and the density of the solution. Then, you can use the formula: Molarity (percent concentration density) / (molecular weight 100).
The percent ionization of ammonia depends on the concentration and the dissociation constant of the substance. Can you please provide the concentration for a more accurate calculation?
gold at 13%
0.03 percent, obviously!
21 percent.
Presumably, 0.6 percent.
Calculating concentration of a chemical solution is a basic skill all students of chemistry must develop early in their studies. What is concentration?
Percent per mass example: uranium concentration in granite is approh. 4 mg/kg. Percent per volume: uranium concentration in ocean water is approx. 4 micrograms/L.
As you increase the concentration of the solution, the concentration of H+ does not change. Meaning, the concentration ionized does not change. Just the original concentration increases. Since percent ionization = (concentration ionized)/(original concentration) , and the original concentration is increased, the percent ionization therefore decreases.
23 percent
0.084%
The cell will lose water by osmosis because water will move from an area of higher concentration (inside the cell, 90% water) to an area of lower concentration (outside the cell, 80% water). This movement of water will continue until the concentrations of water inside and outside the cell reach equilibrium.
The concentration of oxygen in water is 88,88 %.