ask OC transpo
Yes, a bus topology connects all devices in a network to a single communication line, known as the backbone. Each device taps into this backbone to send and receive data, which allows for a straightforward and cost-effective network setup. However, if the backbone fails, the entire network goes down, making it less reliable than other topologies.
The common network of bus topology is a network where clients are connected through cables called a bus. You can learn more about this at the Wikipedia. Once on the website, type "Bus network" into the search field at the top of the page and press enter to bring up the information.
Ease of operation Reliability Low Cost
In a bus topology, the purpose of a terminator is to absorb signals at both ends of the bus cable, preventing them from bouncing back and causing network interference. Without terminators, signals could reflect back along the bus, leading to data collisions and communication errors. By ensuring proper signal termination, terminators help maintain the integrity of data transmission across the network.
the rest of the network is unaffected but if a channel fails then the whole network fails.
Computer
The advantage is in fault detection; in a bus topology any break in any wire segment would cause the entire LAN to fail. With a star topology, a break in any wire segment only affects the one client connected to the network.
yes
Bus topology is the most popular topology. Justify.
No, within a bus topology, the client PC's are indepentent of each other. So if PC 1 fails, PC 2 will still be connected to the server. But, PC 2 won't be able to get data/information from PC 1.
bus topology
Bus Topology.
If the ends of a bus topology network are not terminated then you will get 'signal bounce'. This will cause all packets to collide with each other, and the net effect is that the network is unusable.
Bus topology is extended via the use of repeaters.
bus topology
Any connection failure in a bus topology will result in the network becoming unusable due to signal bounce in the affected cable.