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Yes, decidable languages are closed under concatenation.

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Q: Are decidable languages closed under concatenation?
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Related questions

Are decidable languages closed under any operations?

Yes, decidable languages are closed under operations such as union, intersection, concatenation, and complementation. This means that if a language is decidable, performing these operations on it will result in another decidable language.


Are decidable languages closed under intersection?

Yes, decidable languages are closed under intersection.


Are recognizable languages closed under concatenation?

Yes, recognizable languages are closed under concatenation.


Are Turing recognizable languages closed under concatenation?

Yes, Turing recognizable languages are closed under concatenation.


Are context-free languages closed under concatenation?

Yes, context-free languages are closed under concatenation.


What are the closure properties of regular sets?

;: Th. Closed under union, concatenation, and Kleene closure. ;: Th. Closed under complementation: If L is regular, then is regular. ;: Th. Intersection: .


Is the class of recognizable languages closed under complementation?

No, the class of recognizable languages is not closed under complementation.


Is the class of undecidable languages closed under complementation?

No, the class of undecidable languages is not closed under complementation.


Is the set of nonregular languages closed under intersection?

No, the set of nonregular languages is not closed under intersection.


Are Turing recognizable languages closed under intersection?

Yes, Turing recognizable languages are closed under intersection.


Are Turing recognizable languages closed under union?

Yes, Turing recognizable languages are closed under union.


Is a rational number closed under addition?

No. A number cannot be closed under addition: only a set can be closed. The set of rational numbers is closed under addition.