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To prove that 2n1 o(2n), we need to show that the growth rate of 2n1 is strictly less than the growth rate of 2n as n approaches infinity. This can be demonstrated by using the formal definition of little-o notation and showing that the limit of (2n1) / 2n as n approaches infinity is equal to 0.

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Q: Can you prove that 2n1 o(2n)?
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