0
To find a spanning tree in a given graph, you can use algorithms like Prim's or Kruskal's. These algorithms help identify the minimum weight edges that connect all the vertices in the graph without forming any cycles. The resulting tree will be a spanning tree of the original graph.
Still curious? Ask our experts.
Chat with our AI personalities
Taiga
Beau
BlakeAdd your answer:
Earn +20 pts
Does every possible minimal spanning tree of a given graph have an identical number of edges?
No, not every possible minimal spanning tree of a given graph has an identical number of edges.
How can one find the minimum spanning tree (MST) in a given graph?
To find the minimum spanning tree (MST) in a given graph, you can use algorithms like Prim's or Kruskal's. These algorithms help identify the smallest tree that connects all vertices in the graph without forming any cycles. By selecting the edges with the lowest weights, you can construct the MST efficiently.
What is the pseudocode for implementing the Kruskal algorithm to find the minimum spanning tree of a graph?
The pseudocode for implementing the Kruskal algorithm to find the minimum spanning tree of a graph involves sorting the edges by weight, then iterating through the sorted edges and adding them to the tree if they do not create a cycle. This process continues until all vertices are connected.
What is the minimum spanning tree of an undirected graph g?
The minimum spanning tree of an undirected graph g is the smallest tree that connects all the vertices in the graph without forming any cycles. It is a subgraph of the original graph that includes all the vertices and has the minimum possible total edge weight.
Prove that a graph G is connected if and only if it has a spanning tree?
Proving this is simple. First, you prove that G has a spanning tree, it is connected, which is pretty obvious - a spanning tree itself is already a connected graph on the vertex set V(G), thus G which contains it as a spanning sub graph is obviously also connected. Second, you prove that if G is connected, it has a spanning tree. If G is a tree itself, then it must "contain" a spanning tree. If G is connected and not a tree, then it must have at least one cycle. I don't know if you know this or not, but there is a theorem stating that an edge is a cut-edge if and only if it is on no cycle (a cut-edge is an edge such that if you take it out, the graph becomes disconnected). Thus, you can just keep taking out edges from cycles in G until all that is left are cut-gees. Since you did not take out any cut-edges, the graph is still connected; since all that is left are cut-edges, there are no cycles. A connected graph with no cycles is a tree. Thus, G contains a spanning tree. Therefore, a graph G is connected if and only if it has a spanning tree!
