No, it is not necessarily true that if language A is regular and language B reduces to A, then language B is also regular.
Yes, it is true that a context-free language is a superset of a regular language.
The keyword "pumping lemma" can be used to prove that a language is regular by showing that any sufficiently long string in the language can be divided into parts that can be repeated or "pumped" to create more strings in the language. If this property holds true for a language, it indicates that the language is regular.
Yes, it is true that if a language is undecidable, then it must be infinite.
No, not all deterministic finite automata (DFA) are decidable. Some DFAs may lead to undecidable problems or situations.
No, it is not necessarily true that if language A is regular and language B reduces to A, then language B is also regular.
Yes, it is true that a context-free language is a superset of a regular language.
true
Every human being born on this planet has a soul. So the number always remains a finite number. So the belief is true.
The keyword "pumping lemma" can be used to prove that a language is regular by showing that any sufficiently long string in the language can be divided into parts that can be repeated or "pumped" to create more strings in the language. If this property holds true for a language, it indicates that the language is regular.
No no its a true vector for infinite angular displacement
true
There are an infinite number of numbers. So there is no such thing as "the biggest number in the world". For every (finite) number you can find one bigger than it.
It is true. A line segment has finite length but no width.
No no its a true vector for infinite angular displacement
It's very difficult to answer a yes/no question with 'true' or 'false'.A regular hexagon has 6 obtuse interior angles.A hexagon that's not regular can have fewer than 6 .
A discrete topology on the integers, Z, is defined by letting every subset of Z be open If that is true then Z is a discrete topological space and it is equipped with a discrete topology. Now is it compact? We know that a discrete space is compact if and only if it is finite. Clearly Z is not finite, so the answer is no. If you picked a finite field such a Z7 ( integers mod 7) then the answer would be yes.