Divide 192.168.1.024 into 4 subnets

Answer 1

I guess the network address is 192.168.1.0/24. This can be subnetted if we take two bits from host part to network part. 192.168.1.0/24 in binaries...

11000000.10101000.00000001.00000000 - IP Address

11111111.11111111.11111111.00000000 - Subnet Mask

Take two bits from host part to network part

11000000.10101000.00000001.00 000000 - IP Address

11111111.11111111.11111111.11 000000 - Subnet Mask

Now we get four networks...

1)

11000000.10101000.00000001.00 000000 - IP Address

11111111.11111111.11111111.11 000000 - Subnet Mask

192.168.1.0 - IP Address

255.255.255.192 - Subnet Mask

2)

11000000.10101000.00000001.01 000000 - IP Address

11111111.11111111.11111111.11 000000 - Subnet Mask

192.168.1.64 - IP Address

255.255.255.192 - Subnet Mask

3)

11000000.10101000.00000001.10 000000 - IP Address

11111111.11111111.11111111.11 000000 - Subnet Mask

192.168.1.128 - IP Address

255.255.255.192 - Subnet Mask

4)

11000000.10101000.00000001.11 000000 - IP Address

11111111.11111111.11111111.11 000000 - Subnet Mask

192.168.1.192 - IP Address

255.255.255.192 - Subnet Mask

We get four networks and the networks are

1) 192.168.1.0/26

2) 192.168.1.64/26

3) 192.168.1.128/26

4) 192.168.1.192/26

Refer:

http://www.omnisecu.com/tcpip/internet-layer-ip-subnetting-part1.htm

Answer 2

192.168.1.0

192.168.1.64

192.168.1.128

192.168.1.192

Answer 3

192.168.1.0/30. How many hosts can you have on this network?