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A scientist immerses an irregularly shaped object into a beaker of water and notes how far the water rises.What property of the object is the scientist measuring?
The amount the water rises is dependent of the volume of water displaced by the object - thus it can be used to measure the volume of the immersed object. If the object did not immerse completely - if it floated - the displaced fluid could instead be used to calculate the relative density of the object - when combined with the total volume.
Could the water displacement method be used to determine the volume of a rectangular object as well as an irregularly shaped object?
Yes. It doesnt have to be a irregular even though sometimes it is easier just to do the math... for a rectangular object. l x w x h= volume
How do you find volume when mass and density are not givin?
It depends on the way the question is asked. If you are dealing with a cubic or rectangular object, you measure the length, width, and height, and multiply them. If it is a spherical or irregularly shaped object, you could used water displacement to find its volume. If it's a liquid, you could use a graduated cylinder to measure its volume.
Could the water displacement method be used to determine the volume of a regular shaped object as well as an irregular shaped object?
Yes
How the volume of a heavy irregularly shaped object may be determined experimentally are there any limitations?
The volume of a heavy irregularly shaped object can be determined experimentally using water displacement method - submerging the object in a known volume of water and measuring the increase in water level. Limitations may include buoyancy effects, difficulty in accurately measuring small volume changes, and water absorption by porous objects.
How can the volume of a irregularly shaped rock be measured?
One way would be to get a container into which you could put the rock completely, fill it to the brim with water (without the rock in it), then put the rock in and measure the volume of the water that flowed out.
Why do you need to use the water displacement method for some objects and not others?
The water displacement method is used to find the volume of irregularly shaped objects. This method is not necessary for regularly shaped objects whose volume can be easily calculated using geometric formulas. Irregularly shaped objects do not have a straightforward formula for volume calculation, hence the need for the water displacement method.
Volume of an irregulary shaped object?
To find the volume of an irregular object you may use water displacement. This is basically measuring an amount of water in a graduated cylinder, adding the object, and seeing how much the water level rises. Since 1mL=1cm3, the difference in the two water levels is the volume of the object in cubic centimeters.
What equipment would you use to find the volume of an irregular shaped object?
You could use a water displacement method, where you submerge the object in a graduated cylinder filled with water and measure the change in water volume. Alternatively, you could use a 3D scanner to create a digital model of the object and calculate the volume from the model.
Why do you need to use water displacement method for some objects and not for others?
Because some objects have an irregular shape, therefore cannot be measured like a square could.
How could you work out the volume of an irregular shaped object?
You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.You could immerse it in a liquid, and measure the volume of the displaced liquid.You could also use integration techniques.
How do you measure the volume of an object?
If its regular (geometric shaped) you could just measure it with a ruler using the formula for the shape in question. Irregular shaped objects can be submerged in water. The difference in the water level before and after submersion equals the volume of the object.length X width X height
