To convert cubic inches to gallons, divide cubic inches by 231:
To determine the volume of a 24x48 inch drum in gallons, first calculate the volume in cubic inches: the formula for the volume of a cylinder is πr²h. The radius (r) is half of the diameter (24 inches), which is 12 inches. The height (h) is 48 inches, so the volume is π(12²)(48) ≈ 18,095 cubic inches. Since there are 231 cubic inches in a gallon, the drum holds approximately 78.4 gallons of water.
Volume = 55 gallons = 12,705 cubic inches = 7.3524 cubic feet (rounded)
To determine how many yards of gravel fit into a 55-gallon drum, you first need to convert gallons to cubic yards. A 55-gallon drum holds about 0.2 cubic yards (since 1 cubic yard equals 201.97 gallons). Therefore, approximately 0.2 cubic yards of gravel can fit into a 55-gallon drum.
A 55-gallon drum equates to about 7.35 cubic feet of volume.
Oh, what a delightful question! A 55-gallon drum is about 0.7 cubic yards in size. Just imagine all the wonderful things you could create or store in that much space. Keep exploring and creating, my friend!
12,509.9 cubic inches.
A cylinder 30 inches in diameter and 48 inches tall will have a volume of 33929 cubic inches. V=PI*r*r*H (V=3.1416*15*15*48) That volume is equal to 146.9 gallons (USA). (1 gal = 231 cubic inches)
There are approximately 7.4 cubic feet in 55 gallons.
To calculate the volume of concrete needed to fill a 55-gallon drum, you first need to know the dimensions of the drum. Once you have the dimensions, you can use the formula for the volume of a cylinder (V = πr^2h) to calculate the volume of concrete required. Remember to convert the volume from gallons to cubic inches or feet for accurate results.
1 cubic foot = 1,728 cubic inches1 gallon = 231 cubic inches42 gallons = (42 x 231) cubic inches = (42 x 231 / 1,728) = 5.6146 cubic feet (rounded)
1 US gallon = 0.133680556 cubic feet so about 7 1/3 in a 55 gallon drum
pi*radius2*height = volume in cubic units pi*12.52*48 = 23561.9449 cubic inches